6.022*1023
5.10 grams phosphorous (1 mole P/30.97 grams)(6.022 X 10^23/1 mole P) = 9.92 X 10^22 atoms of phosphorous
1.2 g Cu * (1 mole Cu / 63.54 g Cu)*(6.022x1023 atoms Cu / mole Cu)1.137x1022 atoms of copper
3.22e23 atoms
There are 6.02 x 10 ^ 23 atoms or molecules of a substance in one mole of that substance. This is Avogadro's number.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
6.02 x 1023
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
1 mole of any element = 6.02 × 1023 atoms
By saying Avogadro's number of atoms, you are saying one mole (or 6.02 × 1023 atoms). And one mole of any elements is its atomic mass. Phosphorus' atomic mass is 31.0 grams
5.10 grams phosphorous (1 mole P/30.97 grams)(6.022 X 10^23/1 mole P) = 9.92 X 10^22 atoms of phosphorous
Avogadro's number: 6.02 × 1023. A mole of anything is Avogadro's number.
1 mole = 6.022e23 atoms 8.25 mole = 4.96815 e 24 atoms
1.2 g Cu * (1 mole Cu / 63.54 g Cu)*(6.022x1023 atoms Cu / mole Cu)1.137x1022 atoms of copper
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
1 mol of anything = 6.022x1023 atomsso 1.4 mole = 1.4 * 6.022x1023 atoms / mole = 8.4308x1023 atoms
3.22e23 atoms
There are 6.02 x 10 ^ 23 atoms or molecules of a substance in one mole of that substance. This is Avogadro's number.