There are 58.6934 gram in one mole of Ni atoms, so there are125(g Ni) / 58.6934 (g.mol-1 Ni) = 2.13 moles in 125 gram Ni
6.02 X 1023 particles per mole X .75 moles = 4.52 X 1023 molecules.
Ni(OH)2 1 atom of nickel 2 atoms of oxygen 2 atoms of hydrogen -------------------------------+ total atoms = 5 atoms
According to the U.S. mint the nickels currently in circulation weigh 5.000 grams and contain 25% Ni (the rest is copper). 25% of 5.000g = 1.250 grams of Ni in a nickel coin / molar mass of Ni 58.71 g/mol = 0.02129 moles of Ni times the number of particles for one mole 6.02x10^23 = 1.28x10^22 atoms of Ni in one coin. All together: (0.25 x 5.000g) / (58.71 g per mol) x (6.02x10^23 atoms per mol) = 1.28x10^22 atoms Ni per coin.
As usual, go for the moles. 10.42 grams Ni (1 mole Ni/58.69 grams) = 0.1775 moles Ni 4.38 grams C ( 1 mole C/12.01 grams) = 0.36469 moles C 5.10 grams N (1 mole N/14.01 grams) = 0.36403 mole N Now, the least mole value represents the whole number 1 and it divides the other numbers to get the whole numbers for the subscripts. 0.36469 mole C/0.1775 mole Ni = 2.05, call it 2 0.36403 mole N/0.1775 mole Ni = 2.05, also called 2 As you gave the species order ( though I am not sure of this ) NiC2N2
500,000 atoms * 1 mole Ni/6.022*1023 atoms * 58.693 grams/1 mole Ni = 4.873*10-17 grams Therefore, the mass of 500,000 atoms of nickel is about 4.87*10-17 grams
There are 58.6934 gram in one mole of Ni atoms, so there are125(g Ni) / 58.6934 (g.mol-1 Ni) = 2.13 moles in 125 gram Ni
6.02 X 1023 particles per mole X .75 moles = 4.52 X 1023 molecules.
Ni(OH)2 1 atom of nickel 2 atoms of oxygen 2 atoms of hydrogen -------------------------------+ total atoms = 5 atoms
According to the U.S. mint the nickels currently in circulation weigh 5.000 grams and contain 25% Ni (the rest is copper). 25% of 5.000g = 1.250 grams of Ni in a nickel coin / molar mass of Ni 58.71 g/mol = 0.02129 moles of Ni times the number of particles for one mole 6.02x10^23 = 1.28x10^22 atoms of Ni in one coin. All together: (0.25 x 5.000g) / (58.71 g per mol) x (6.02x10^23 atoms per mol) = 1.28x10^22 atoms Ni per coin.
As usual, go for the moles. 10.42 grams Ni (1 mole Ni/58.69 grams) = 0.1775 moles Ni 4.38 grams C ( 1 mole C/12.01 grams) = 0.36469 moles C 5.10 grams N (1 mole N/14.01 grams) = 0.36403 mole N Now, the least mole value represents the whole number 1 and it divides the other numbers to get the whole numbers for the subscripts. 0.36469 mole C/0.1775 mole Ni = 2.05, call it 2 0.36403 mole N/0.1775 mole Ni = 2.05, also called 2 As you gave the species order ( though I am not sure of this ) NiC2N2
You can not have 0.4 of an atom (of anything). Thus you question makes no sense.
3 Ni(OH)2 contain six oxygen atoms.
1 mole of nickel is 58.69 grams. 176.1 g Ni * (1 mol Ni/58.69 g Ni) = 3.0005 mol Ni Therefore, 176.1 grams of nickel is equal to 3 moles of nickel.
1 mole Ni = 58.6934g 1g = 1000mg 2.63mol Ni x 58.6934g Ni/mol = 154g Ni 154g Ni x 1000mg/g = 154000mg Ni
Nickel is 58.7g/mol, so 26.4/58.7=0.45mol, and that times 6.02x1023 (Avogadro's number) gives you 2.71x1023 atoms of nickel.
Nickel Hydroxide is Ni(OH)2. So 1 molecule of Nickel Hydroxide contains 2 oxygen atoms.