Pb has a MW of 207.2 g/mol. Thus, 80g of Pb is 80/207.2 = 0.39 mol of lead. Using Avogadro's number: (6.0221415 * 1023 atoms/mol)(0.39 mol) = 2.349 * 1023 atoms.
Pb molecular weight is 207.2 g/mol. 33.3 moles of Pb weighs 6899.76 grams.
207.2/ 6.022*10^23 = 34.4 x 10-23 g, mass of 1 Pb atom For two atoms: 34.4*2= 68.8 x 10-23 g Pb 5.1*10^-23*4.003 g He (atomic mass) / 1 mol He= 20.4*10^-23 g He And the mass of lead is greater.
That is equal to 0.65 (mol Pb) * 207.2 (g/mol Pb) = 135 grams Pb 207.2 = molar mass of Pb, lead.
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
The number of atoms of lead is 6,68.10e23.
The number of atoms of lead is 6,68.10e23.
A lot! 9.51 X 103 grams Pb (1 mole Pb/207.2 grams) = 45.9 moles of lead ===============
Pb has a MW of 207.2 g/mol. Thus, 80g of Pb is 80/207.2 = 0.39 mol of lead. Using Avogadro's number: (6.0221415 * 1023 atoms/mol)(0.39 mol) = 2.349 * 1023 atoms.
Pb molecular weight is 207.2 g/mol. 33.3 moles of Pb weighs 6899.76 grams.
207.2/ 6.022*10^23 = 34.4 x 10-23 g, mass of 1 Pb atom For two atoms: 34.4*2= 68.8 x 10-23 g Pb 5.1*10^-23*4.003 g He (atomic mass) / 1 mol He= 20.4*10^-23 g He And the mass of lead is greater.
None. When NH reacts there is no Pb involved and so there is none formed.
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
149 g of calcium contain 22,39.10e23 atoms.
Solve for the masses of oxygen given 1 gram of Pb:For PbO:(1 g Pb)(1 mol Pb/207.2 g Pb)(1 PbO/1 Pb)(1 O/1 PbO)(16 g O/1 mol O) = 0.07722 g OFor PbO2:(1 g Pb)(1 mol Pb/207.2 g Pb)(1 PbO2/1 Pb)(2 O/1 PbO2)(16 g O/1 mol O) = 0.1544 g OFor Pb2O3:(1 g Pb)(1 mol Pb/207.2 g Pb)(1 Pb2O3/2 Pb)(3 O/1 Pb2O3)(16 g O/1 mol O) = 0.1158 g OGet the ratio by dividing the smallest mass of oxygen to the rest of the calculated masses then multiply it by a certain factor to make it a whole number:0.07722 / 0.07722 = 1 x 2 = 20.1544 / 0.07722 = 2 x 2 = 40.1158 / 0.07722 = 1.5 x 2 = 3ANSWER: 2:4:3
6,687.1023 chlorine atoms
27,30.10e23 atoms