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1.35
One molecule of SO2 contains 3 atoms: 1 sulfur atom and 2 oxygen atoms.
There are two oxygen atoms in SO2.
No, SO2 is a molecule composed of two oxygen atoms bonded to a sulfur atom.
In sulfur dioxide (SO2), there is one sulfur (S) atom and two oxygen (O) atoms.
There are 4 oxygen atoms in 1 molecule of SO2. Therefore, in 1.25 mol of SO2, there would be 5 moles of oxygen atoms (4 * 1.25 = 5). Using Avogadro's number, we can determine that there are 3.01 x 10^24 oxygen atoms in 1.25 mol of SO2.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
How many moles of C are needed to react with 0.490 mole SO2?
To find the number of moles in 3.82 g of SO2, you need to use the molar mass of SO2. The molar mass of SO2 is 64.07 g/mol. So, 3.82 g of SO2 is equal to 3.82/64.07 ≈ 0.06 moles.
To find the number of moles in 128 grams of sulfur dioxide, divide the given mass by the molar mass of SO2. The molar mass of SO2 is 32.07 g/mol (sulfur) + 2*(16.00 g/mol) (2 oxygen atoms) = 64.07 g/mol. Thus, there are 2 moles of SO2 in 128 grams.
To determine the number of moles of SO2 in 0.45 grams of sulfur dioxide, you need to use the molar mass of SO2. The molar mass of SO2 is about 64.06 g/mol. Divide the given mass by the molar mass to find the number of moles. In this case, 0.45 grams divided by 64.06 g/mol gives you approximately 0.007 moles of SO2.
For the reaction SO2 + O2 -> SO3, the stoichiometry is 1:1. So, if 4 moles of SO2 are oxidized, then 4 moles of O2 are required for the complete reaction.
1 mole of sulfur reacts with 2 moles of oxygen to produce 1 mole of SO2. Therefore, to produce 0.567 moles of SO2, you would need to burn 0.2835 moles of sulfur.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
To determine the number of gram-moles in 320 grams of SO2, you first need to find the molar mass of SO2, which is 64.07 g/mol. Then you divide the given mass (320 g) by the molar mass to get the number of moles. Therefore, 320 grams of SO2 is equivalent to 5 moles.
The stoichiometry of the reaction between sulfur dioxide and oxygen to produce sulfur trioxide is 2SO2 + O2 -> 2SO3. This means that 2 moles of SO3 are formed from 2 moles of SO2. Therefore, if 3 moles of SO2 are used, 3/2 = 1.5 moles of SO3 will be formed.