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1.53x10^26
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∙ 10y ago
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How many O atoms in 1.25 mol of SO2?
There are 4 oxygen atoms in 1 molecule of SO2. Therefore, in 1.25 mol of SO2, there would be 5 moles of oxygen atoms (4 * 1.25 = 5). Using Avogadro's number, we can determine that there are 3.01 x 10^24 oxygen atoms in 1.25 mol of SO2.
How many atoms are in Ba OH 2?
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
How many atoms of O are in 3.65 mol of sucrose?
Sucrose has a chemical formula of C12H22O11, so it contains 11 oxygen atoms per molecule. In 3.65 mol of sucrose, the number of molecules can be calculated using Avogadro's number, and then multiplied by the number of oxygen atoms per molecule to find the total number of oxygen atoms. Therefore, in 3.65 mol of sucrose, there are 2.45 x 10^24 oxygen atoms.
How many O atoms are in 3.15 mol of SnO2?
There are approximately 3.02 x 10^24 oxygen atoms in 3.15 mol of SnO2. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of oxygen atoms in SnO2 (2 moles of oxygen per 1 mole of SnO2).
How many atoms are present in 16g of O and 8g of S?
In 16g of O, there are (16 g \times \frac{1 \text{mol}}{16.00 g} \times 6.022 \times 10^{23} \text{atoms/mol} = 6.022 \times 10^{23} \text{atoms}) of O. Similarly, in 8g of S, there are (8 g \times \frac{1 \text{mol}}{32.07 g} \times 6.022 \times 10^{23} \text{atoms/mol} = 1.506 \times 10^{23} \text{atoms}) of S.
How many O atoms in 1.25 mol of SO2?
There are 4 oxygen atoms in 1 molecule of SO2. Therefore, in 1.25 mol of SO2, there would be 5 moles of oxygen atoms (4 * 1.25 = 5). Using Avogadro's number, we can determine that there are 3.01 x 10^24 oxygen atoms in 1.25 mol of SO2.
How many moles of oxygen atoms are in 2.53 g of calcium hydroxide?
The answer is 0,068 mol (for O not for O2).
How many atoms are in 16 grams of oxygen?
1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O
Calculate the number of atoms of O contained in 16.0 pounds of O?
To calculate the number of oxygen atoms in 16.0 pounds of oxygen, first convert 16.0 pounds to grams (1 pound ≈ 453.592 grams). Then, calculate the number of moles of oxygen using the molar mass of oxygen (16.00 g/mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of oxygen atoms.
How many atoms are in Ba OH 2?
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
How many atoms of O are in 3.65 mol of sucrose?
Sucrose has a chemical formula of C12H22O11, so it contains 11 oxygen atoms per molecule. In 3.65 mol of sucrose, the number of molecules can be calculated using Avogadro's number, and then multiplied by the number of oxygen atoms per molecule to find the total number of oxygen atoms. Therefore, in 3.65 mol of sucrose, there are 2.45 x 10^24 oxygen atoms.
How many O atoms are in 3.15 mol of SnO2?
There are approximately 3.02 x 10^24 oxygen atoms in 3.15 mol of SnO2. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of oxygen atoms in SnO2 (2 moles of oxygen per 1 mole of SnO2).
How many atoms are present in 16g of O and 8g of S?
In 16g of O, there are (16 g \times \frac{1 \text{mol}}{16.00 g} \times 6.022 \times 10^{23} \text{atoms/mol} = 6.022 \times 10^{23} \text{atoms}) of O. Similarly, in 8g of S, there are (8 g \times \frac{1 \text{mol}}{32.07 g} \times 6.022 \times 10^{23} \text{atoms/mol} = 1.506 \times 10^{23} \text{atoms}) of S.
How many atoms are in 12.54 g of O2?
12.54 (g O2) / 2*15.99 (g/mol O2) = 0.3921 mol O2 -->0.3921 (mol O2) * 6.022*1023 (molecules O2)/(molO2) == 2.361*1023 molecules O2= 4.723*1023 atoms O
How many grams of oxygen are in 16.0g of fructose?
16.0 g Fru = [16 (g) / 180 (g/mol Fru)] * [6 (mol O) / 1 (mol Fru)] * 16 (g O)/mol O) = 8.53 g O
How many moles of atoms are in 4.1 x 10-12g O?
To find the number of moles of atoms in 4.1 x 10^(-12) g of oxygen, you first convert the mass to moles by dividing by the molar mass of oxygen (16 g/mol). 4.1 x 10^(-12) g / 16 g/mol = 2.56 x 10^(-13) moles of oxygen atoms.
How many atoms of oxygen are in 3.33 grams of magnesium hydroxide?
To find the number of oxygen atoms in 3.33 grams of magnesium hydroxide, you first need to calculate the moles of magnesium hydroxide using its molar mass. Then, since the formula of magnesium hydroxide is Mg(OH)2, there are 2 oxygen atoms in each formula unit. Finally, multiply the number of moles by Avogadro's number to get the number of oxygen atoms.
