First you need to find the Atomic Mass of magnesium, 24.3 grams.
Then you can do a simple conversion:
Grams ÷ Atomic mass = Moles
7.5 grams ÷ 24.3 grams = 0.309 moles Mg
One mole equals 6.02 x 10 raised to the power 23 units of anything. In other words, 1 mole is simply the number 6.02 x 10 raised to the power 23. Therefore, the number of atoms in 3.2 moles of magnesium is computed as follows:
3.2 x 6.02 x 10 raised to the power 23
5.55 moles Mg ((6.022 × 1023) ÷ 1 mol Mg) = 3.34 × 1024 atoms of Mg
1 mole of Mg contains 6.02 x 1023 Mg atoms.
Accordingly, 7.21 moles of Mg contains 7.21 x 6.02 x 1023 = 4.34 x 1024 Mg atoms.
hi
4,515.10e24 atoms of magnesium is equal to 7,5 moles.
0.05 moles O3 (6.022 X 1023/1 mole O3) = 3.01 X 1022 atoms of ozone ======================
From the formula, you have 2 atoms of Magnesium combine with one oxygen molecule to form 2 molecules of magnesium oxide. So when 4 magnesium atoms combine with two molecules of oxygen you get 4 magnesium oxide molecules. So from 4 moles of magnesium you get 4 moles of Magnesium oxide.
1 mole of any element contain 6,022 140 857.1023 atoms (Avogadro number).2,5 moles of magnesium contain 15,0553521425.1023.
There are 0.13 moles in 20 grams of magnesium nitrate.
4,515.10e24 atoms of magnesium is equal to 7,5 moles.
Since there are no subscripts, there is .800 moles of Oxygen atoms and .800 moles of Magnesium because there is .800 moles of the compound.
There are 6.022*10^23 atoms per mole so: 1.1*10^22Ag atoms* 1mole/6.022*10^23atoms = 0.018Ag moles
0.050 moles silver (6.022 X 1023/1 mole Ag) = 3.01 X 1022 atoms of silver --------------------------------------
0.05 moles O3 (6.022 X 1023/1 mole O3) = 3.01 X 1022 atoms of ozone ======================
From the formula, you have 2 atoms of Magnesium combine with one oxygen molecule to form 2 molecules of magnesium oxide. So when 4 magnesium atoms combine with two molecules of oxygen you get 4 magnesium oxide molecules. So from 4 moles of magnesium you get 4 moles of Magnesium oxide.
0.106 moles Lithium (6.022 X 1023/1 mole Li) = 6.38 X 1022 atoms of Lithium ======================
1 mole of any element contain 6,022 140 857.1023 atoms (Avogadro number).2,5 moles of magnesium contain 15,0553521425.1023.
Glucose has a molar mass of 180. There are thus 0.1 moles present in 18 g. 1 mole contains 6.022 x 1023 molecules. 0.1 moles contains 6.022 x 1022 molecules and so glucose with 24 atoms per molecule contains 24 x 6.022 x 1022 = 1.44528 x 1024 atoms.
how many atoms are there in magnesiumoxide 2 atoms are in magnesium 2 atoms are in magnesium
A mole (more properly called a "gram atomic mass") of K contains Avogadro's Number of atoms. Therefore, 0.0384 moles contains 0.0384 X Avogadro's Number or about 2.31 X 1022 atoms, to the justified number of significant digits.
A sample of 56,4 of magnesium is equal to 2,32 moles.