A mole (more properly called a "gram Atomic Mass") of K contains Avogadro's Number of atoms. Therefore, 0.0384 moles contains 0.0384 X Avogadro's Number or about 2.31 X 1022 atoms, to the justified number of significant digits.
1 mole K = 6.022 x 1023 atoms KConvert known moles to atoms.0.0671mol K X (6.022 x 1023 atoms K/1mol K) = 4.04 x 1022 atoms K
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1
If you have 2 moles of K+ for every mole of K2S and Molarity (M) is Moles per Liter. Then you know that you have .30 M of K2S. The way that you do that is setting up a series of conversion factors like so:(.15moles k2s/liter) x (2 moles of K/ 1 mole of K2S) = .30 moles k/ liter.The moles of K2S cancel out and you are left with moles of K per liter.
2.60 moles There are 2 moles of K in K2SO4. the total moles times two (1.3 x 2) is 2.60 moles.
Use the ideal gas equation to get moles of water vapor. PV = nRT (1 atm)(131.97 L) = n(0.08206 L*atm/mol*K)(298.15 K) = 5.3939 moles H2O (6.022 X 10^23/1 mole H2O) = 3.2482 X 10^24 atoms of water vapor --------------------------------------------------------
0.3 moles K (6.022 X 10^23/1mol K) = 1.8 X 10^23 atoms of K
0.0384 moles K x 6.02x10^23 atoms/mole = 2.31x10^22 atoms
1 mole K = 6.022 x 1023 atoms KConvert known moles to atoms.0.0671mol K X (6.022 x 1023 atoms K/1mol K) = 4.04 x 1022 atoms K
To produce potassium nitride (K₃N), the balanced chemical equation is 6 K + N₂ → 2 K₃N. This indicates that 6 moles of potassium are required to produce 2 moles of potassium nitride. Therefore, to produce 2.0 moles of K₃N, you would need 6 moles of potassium.
There are 6.022 × 1023 atoms of potassium in every mole of potassium. Since one mole of KOH contains one mole of K, the answer is 6.022×1023 atoms of K. Therefore, 3.5 moles * 6.022E23 atoms/1 mole= 2.107E24
There are 1 mole of atoms in 6.022 x 10^23 atoms (Avogadro's number). Therefore, to find the number of moles in 6.81 x 10^24 atoms, you would divide the given number of atoms by Avogadro's number: 6.81 x 10^24 atoms / 6.022 x 10^23 atoms/mole = 11.33 moles.
To find the number of atoms in 3.8 moles of potassium (K), you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms per mole. Multiply the number of moles by Avogadro's number: [ 3.8 , \text{mol} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 2.28 \times 10^{24} , \text{atoms}. ] Therefore, there are approximately (2.28 \times 10^{24}) atoms in 3.8 moles of potassium.
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
If you have 0.5 moles of K₂CO₃, then you simply have 0.5 moles of K₂CO₃. The quantity of moles is a direct measurement, so there are no additional calculations needed. Therefore, the answer is 0.5 moles of K₂CO₃.
1 fomula unit of KOH has 3 atoms: 1 potassium (K), 1 oxygen (O), and 1 hydrogen (H).
To find the number of K atoms in KCl, we first calculate the molar mass of KCl: 39.10 (K) + 35.45 (Cl) = 74.55 g/mol. Next, we determine the number of moles of KCl in 2.77g: 2.77g / 74.55 g/mol = 0.0371 mol. Since there is 1 K atom in 1 KCl molecule, the number of K atoms in 2.77g of KCl is the same as the number of moles of KCl, which is 0.0371 mol.
3.3 moles of K2S 3.3 moles of S-2 6.6 moles of K+1