6.022 x 1023 molecules. This is Avogadro's number and a mole of anything. Since there are three atoms in each molecule, one of Barium and two of Chlorine, the number of atoms is three times that, or 1.807 x 1024.
3
Two
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
89.3
The chemical formula of barium nitrate is Ba(NO3)2; barium nitrate has six oxygen atoms in the molecule.
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
Barium chloride is BaCl2
Two
0.550 mole BaCl2 x 6.02x10^23 formula units/mole x 3 atoms/formula unit = 9.93x10^23 atoms
it is written barium chloride when a compound, and two. BaCl2 :)
Totally three atoms One barium and two chlorine atoms
Two atoms of chlorine are needed, one to accept each of the barium electrons in an ionic compound, barium chloride (BaCl2).
286 (mol BaCl2) * 208.23 (g/mol BaCl2) = 59,553.78 = 59.6*103 g BaCl2 = 59.6 kg BaCl2
3,75 moles barium chloride
Barium gives its two electrons to two chlorine atoms (to form chloride ions) and they form an ionic compound barium chloride.
There are 2. The chemical formula tells you that there is 1 barium and 2 chlorine.
6,36 g of silver chloride are obtained.
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.