286 (mol BaCl2) * 208.23 (g/mol BaCl2) = 59,553.78 = 59.6*103 g BaCl2 = 59.6 kg BaCl2
About 0.013
6.37 g
Barium chloride is BaCl2
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
Barium gives its two electrons to two chlorine atoms (to form chloride ions) and they form an ionic compound barium chloride.
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
89.3
89.3
3,75 moles barium chloride
23.3772 grams are there in four tenths moles of sodium chloride
.73 moles
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
0,40 moles of sodium chloride contain 23,376 g.
About 0.013
257g
9.11 g
10 moles of sodium chloride have 584,397 g.