The amount of moles is also defined as n = N/NA, where
n - amount of moles
N - amount of atoms
NA - Avogadro constant (approx. 6.02214179×1023 mol-1), therefore
N = n×NA = 0.263×6.02214179×1023 = 1,583823291×1023 atoms.
How many atoms are present in a piece of sterlingsilver jewelry weighing 33.14 ? (Sterling silver is a silver-copper alloy containing 92.5% by mass.)
The answer is 6,31 moles Ag.
One formula unit of silver sulfate, Ag2SO4 has 7 atoms.
It depends on the weight of the silver in the material. 107.89 g of silver will have 6.023 x 1023 atoms of silver
48,177 134 32.1023 atoms
How many atoms are present in a piece of sterlingsilver jewelry weighing 33.14 ? (Sterling silver is a silver-copper alloy containing 92.5% by mass.)
The answer is approx. 1,5.10e23 atoms of silver.
Silver is an atom.
Silver is an atom.
29
4
Silver is an element, pure silver would contain only silver atoms.
about 30
The answer is 6,31 moles Ag.
There are 6.022x1023 atoms in a mole. You multiply 6.022x1023 by 8.68, which equals 52.20796x1023 atoms
One formula unit of silver sulfate, Ag2SO4 has 7 atoms.
It depends on the weight of the silver in the material. 107.89 g of silver will have 6.023 x 1023 atoms of silver