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1 Magnesium and 2 Fluoride
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How many atoms are present in 31 grams of magnesium fluoride?
MgF2 has a molecular weight of 24+19*2 = 62g. Thus, 31 grams of MgF2 represent .5mol. There are 6.022*10^23 particles per mole. Since MgF2 has three atoms in it, we can find the number of atoms by the following: (.5 mol)(6.022*10^23 particles/mol)(3 atoms in MgF2) = ... Enjoy your free high school chemistry answer!
Does covalent bond exist between atoms MgF2?
That is ionic bonding as well.
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
Is NCI3 and MgF2 a ionic compound?
NCl3 is not ionic but MgF2 is ionic
Is MgF2 acidic?
No. 'tis a basic salt.
How many atoms are present in 31 grams of magnesium fluoride?
MgF2 has a molecular weight of 24+19*2 = 62g. Thus, 31 grams of MgF2 represent .5mol. There are 6.022*10^23 particles per mole. Since MgF2 has three atoms in it, we can find the number of atoms by the following: (.5 mol)(6.022*10^23 particles/mol)(3 atoms in MgF2) = ... Enjoy your free high school chemistry answer!
Does covalent bond exist between atoms MgF2?
That is ionic bonding as well.
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
Which is the correct interpretation of the formula MgF2?
That's magnesium fluoride: one magnesium atom, two fluorine atoms.
Will fluorine atoms bond?
Yes it will form ionic bond (as in NaF or MgF2) or covalent bond as in F2 or ClF3)
How many fluoride ions in MgF2?
2 ions
Is NCI3 and MgF2 a ionic compound?
NCl3 is not ionic but MgF2 is ionic
What is the formula for magnesium and fluorine?
Magnesium (II) fluoride, MgF2 Formula weight: 62.302 grams/moleSee the Related Questions for how to calculated the molecular weight of any molecule!
How many moles of fluorine molecules react with one mole of magnesium atoms?
One: The formula for magnesium fluoride is MgF2. Since each mole of fluorine molecules, which have the formula F2, contains two moles of fluorine atoms, one mole of each is the right ratio.
Which has a higher melting point LiF or MgF2?
MgF2 is higher that LiF do to the greater bond strength in MgF2. This greater strength is indicated by the charge of Mg (+3) which is higher than the +2 charge of Li. Also the MgF2 is larger in mass.
How do the elements magnesium and fluorine produce the compound magnesium fluoride?
Magnesium atoms lose 2 electrons to form a Mg2+ ion, and fluorine atoms gain 1 electron to form a F- ion. One magnesium ion forms an electrostatic attraction with two fluoride ions. This electrostatic attraction is an ionic bond. The resulting ionic compound is MgF2. Mg2+ + 2F- ---> MgF2
Which solution would elevate the boiling point of water the most MgF2 glucose KNO3 KBr?
MgF2
