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Q: How many atoms does thirty two grams of sulfur contain?
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How many atoms are in 25.1 grams in sulfur?

25,1 grams sulfur contain 4,7147765.10e23 atoms.


How many atoms does g of sulfur contain?

Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.


How many atoms does 32 g sulfur contain?

Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.


How many atoms 32 g of sulfur contain?

Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.


What is the of 3.09x10 24 atoms of sulfur in grams?

3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.


How many sulfur atoms are in 3 grams of sulfur?

1.12875 × 1023


How many atoms are 6.02 grams of sulfur?

6.02 grams sulfur (1mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.13 X 10^23 atoms sulfur


What is the mass of 3.09X1024 atoms of sulfur in grams?

I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams


How many atoms of sulfur are present in 155 g of sulfur?

93,341,000,000,000,000,000,000,000 or 933.41 x 1023 atoms of arsenic. You just take Avogadro's number (6.022 x 1023) and multiply 6.022 by the number of moles (155) and then multiply the product by 1023.


How many atoms of sulfur are in a 48.0 g chunk of sulfur?

48.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 9.01 X 10^23 atoms of sulfur


How many moles of atoms are there in 48.096 grams of sulfur?

Full formal set up. 48.096 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)(1 mole S atoms/6.022 X 1023) = 1.4997 moles of sulfur atoms ---------------------------------------


How many atoms are there in 72.0 g of sulfur?

72.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.35 X 10^24 atoms of sulfur