Think of it like this.
O = C = O
There are three altogether. One carbon atom and two oxygen atoms. :D
This looks like the equation for the complete combustion of methane
CH4 + 2O2 -> CO2 + 2H2O
There are 4 oxygen atoms.
There are two oxygen atoms in a carbon dioxide molecule and one oxygen atom in a water molecule.
Multiply the coefficient (3) by the subscript (2) to obtain 6 total oxygen atoms.
3 carbon
6 oxygen
ten
Two. The equation means two water molecules, H20. Thus you have 4 hydrogens and 2 oxygens.
You have to burn C3H8 in O2. You get 3CO2 plus 4H2O. So to burn one mole of C3H8, you need 5 moles of O2. That means you need one fifth of C3H8 as compared to O2. So you need 0.567/5 = 0.1134 moles of C3H8. Hence the answer.
Okay, a mole of potassium perchlorate contains 6.02x1023 formula units of potassium perchlorate, but you're asking about individual atoms. So, let's look at the formula: KClO3. That's 1 potassium, 1 chlorine, and 3 oxygens, for a total of 5 atoms per formula unit. Now, multiple 5 by Avogadro's number above, to get 30.1x1023, which simplifies to 3.01x1024 atoms.
7 2 sodium atoms 1 sulphur atom and 4 oxygen atoms
Methane - CH4 - has 5 atoms.
The answer is: C3H8 + 5O2 3CO2 + 4H2O
Three different elements: C, H, O. 3 C-atoms 8 H-atoms 10 (=3*2+4) O-atoms
Three different elements: C, H, O. 3 C-atoms 8 H-atoms 10 (=3*2+4) O-atoms
coefficiant
C-carbon H-hydrogen O-oxygen Three different elements.
One molecule of H2O has 3 atoms (two hydrogens and one oxygen). So there will be 12 atoms in 4H2O.
The ratio of propane to oxygen is 1:5. So for every mole of propane, 5 moles of oxygen gas are required for the complete combustion of propane.Balanced equation:C3H8 + 5O2 --> 3CO2 + 4H2O
5048+w4g5=23vm32
There are 5 atoms in silver nitrate (1 silver, 1 nitrogen and 3 oxygens).
One carbon and 2 oxygens = 3
Total of 29 atoms (14 carbon, 12 hydrogen and 3 oxygens).
C6H12O6 is glucose. There are six carbons, twelve hydrogens and six oxygens in each molecule.