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Three bonding pairs, thus a pyramid.
3 bond pairs and no lone pairs
Each iodine atom in a molecule of carbon tetraiodide has three non-bonding pairs of electrons.
One lone pair and three bonding chlorine pairs. General shape is tetrahedral and it's a trigonal pyramidal.
you have 5 binded elektron pairs, and one free pair
3 bonding pairs and one lone pair or non-bonding pair
22
Three bonding pairs, thus a pyramid.
H2CO. The oxygen will have two pairs of non-bonding electrons
SeBr2O only has one lewis structure. you can fill all of the lone pairs without having to use a double bond (double bonds are why there are equivalent lewis structures)
There are three bonding pairs of electrons in BF3. There are 0 nonbinding pairs, but BF3 can accept two more electrons to give it a complete octet
NONE!!! Each bonding electron in carbon is paired with the bonding electron in each of the four hydrogens. So there are no lone pairs.
A single Lewis structure can be used to represent the bonding in SeF2O.
3 bond pairs and no lone pairs
bp-4,lp-1
Cl4 doesn't exist. It should be Cl2 and there will be 4 pairs of non bonding electrons on each chlorine.
An HCl molecule contains 3 nonbonding pairs..