Water evaporation requires 539 calories per gram. However, there is a unit called the large calorie (sometimes abbreviated Cal instead of cal) which is 1000 times larger, so only 0.539 of a large calorie. Nutrition usually means large calorie for calorie.
540
540 calories per gram is absorbed when water vaporizes at its boiling point. Called the latent heat of vaporization. 540 x 23.1 x 18 = 224532 calories
To transform 1 gram of ice at 0 degrees Celsius to 1 gram of water vapor at 100 degrees Celsius, 720 calories are added (absorbed). There are no calories released during the process.
If "heats" means to evaporate, then all of the regularwater would heat up and then evaporate. The ocean waterwould also evaporate, but only the fresh water from the ocean evaporates and the salt or sodium chloride will get left behind. Hope this helps. â—‹
540 calories are needed to turn one gram of water at 100 degrees celsius to steam.
3,965 grams
In 1 gram of what? 1 gram of carbohydrate is 4 calories. 1 gram of protein is 4 calories. 1 gram of fat is 9 calories and 1 gram of alcohol is 7 calories.
First, the water must be raised to a temperature of 100 degrees - this requires 4.181 joule/(degree x gram). For example, if your "room temperature" is 20 degrees, multiply that by 8. Then you have to actually evaporate it - that costs 2260 joules/gram.
1 gram of carbohydrate is equal to 4 calories.
1 calorie (or rather, kilocalorie). This is because the specific heat of water is 1.
It is approximately 539.4 calories per gram.
Heat of Fusion