You use Heat of fusion... Heat=mass x heat of fusion
Heat of fusion for water: 80 cal/g so
35g x 80 cal/g= 2800 cal released.
At 25 degrees Celsius it's about 385 grams NaCl per liter water.
The needed heat is:Q = 10 x 20 x 0,031 = 6,2 calories
6480 calories8LBs X 15 gallons x 54 DEGREES = 6480 CALORIES
80 grams of what? And at what temperature and pressure? If you are asking about water, at 1 atmosphere, at 25 degrees C, then you can say water weighs 1 gram per milliliter.
(75'C)x(1g) < (75'C)x(100g) .'. The second option has more thermal energy.
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
Na3Cl2
700
38.2C-24.5C = 13.7 C change this requires 13.7 calories per gram or 1370 calories total
Grams liquid × mol/g × Hfusion
105C
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
Grams Liquid x mol/g x Hfusion
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
Grams of what?
There are 15 calories in 4 grams of sugar.