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How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
Wiki User
∙ 13y ago
(5)(3)= 15 calories.
1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
Wiki User
∙ 13y ago
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How many calories are required to raise 8 grams of water 7 degrees Celsius?
700
If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?
105C
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
The amount of dietary Calories in one hard-boiled egg could raise the temperature of?
1,000 grams of water by 75 degrees Celsius
How much energy is required to raise 21kg of water by 2 degrees Celsius?
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
A solution has a density of 1.50 grams per milileter at 25.0 degrees Celsius How many grams are needed to obtain 5.00 ml of the solution?
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
How many joules of heat energy must be supplied to 21 g of water to raise the temperature of the water from 24 to 95 degrees Celsius?
21 grams through 71 degrees is 21x71 calories.
What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?
The temperature would be that of water's boilng point od 100 degrees
If 1200 calories of heat is added to 40 grams of water at 20 degree what will be the final temperature?
I believe it will be 145.52 degrees Celsius if I did my math correctly. You need to convert calories to joules. I believe one joule raises the temp of 1 gram water by 1 degree Celsius so 1200*4.184=5020.8 J /40grams=125.52 temp increase+20=145.52 degrees Celsius.
What is the density of sulfur at twenty five degrees Celsius?
The density of sulfur in grams/cm3 is 2.070. (not at twenty five degrees Celsius)
