it has 6 electrons in the outer most shell
Oxygen is a non-metal in the 6A Group, so it needs 2 electrons to reach 8 in its outer shell. Sodium is a metal in the 1A Group, so it has 1 electron in its outer shell to donate. Since the oxygen needs 2, but a sodium can only donate 1, the oxygen will get an electron from two sodium atoms, giving the formula:Na2O
No, lithium does not have a full outer shell. It has 1 electron in its outer shell, which allows it to easily lose that electron to achieve a stable electron configuration.
I think it is that there is only 1 electron in its outer shell.
Hydrogen contains one valence electron (one electron in its outer orbit) and oxygen contains six valence electrons, to become stable a element wants to have 8 electrons in its outer orbit. Therefore when hydrogen and oxygen combine, it will take 2 parts hydrogen and one part oxygen H2O
It would gain or share an electron - in order to complete the outer shell.
The outer electron configuration for oxygen is 2s^2 2p^4. This means that oxygen has 6 outer electrons in its valence shell.
The significance of an outer electron is that it is the (only) electron that can interact with other electrons, rendering it extremely valuable.
the valence is the outer level
Oxygen has 8 electrons (2 in the inner shell, 6 in the outer).
Oxygen will gain two electrons to achieve a full outer shell.
Sodium is an element which has one electron in its outer electron shell, and which can obtain a more stable electron configuration by getting rid of that electron. This causes it to undergo chemical reactions with other elements such as oxygen or chlorine, which need to acquire electrons in order to obtain a more stable electron configuration. If sodium reacts with water, it is reacting with the oxygen in the water molecule. In the case of sodium chloride, the sodium has already reacted with chlorine to form that compound, and has given up its outer electron, so it no longer needs to react with oxygen in water.
Hydrogen contains one valence electron (one electron in its outer orbit) and oxygen contains six valence electrons, to become stable a element wants to have 8 electrons in its outer orbit. Therefore when hydrogen and oxygen combine, it will take 2 parts hydrogen and one part oxygen H2O
the alkali metals have 1 electron in their outer most shell. in order to obtain a full outer shell they have to lose this electron. so when they react with another metal they lose this electron and the outer most shell.
Oxygen is a non-metal in the 6A Group, so it needs 2 electrons to reach 8 in its outer shell. Sodium is a metal in the 1A Group, so it has 1 electron in its outer shell to donate. Since the oxygen needs 2, but a sodium can only donate 1, the oxygen will get an electron from two sodium atoms, giving the formula:Na2O
Oxygen is the final electron acceptor. Oxygen, with it's great electronegativity, pulls electrons through the electron transport chain where these electrons provide the motive force to pump protons into the outer lumen of the mitochondria. When these protons fall down their concentration gradient oxygen is there to pick then up with the electrons and form water.
Oxygen has 6 electrons in its outer shell, and it needs 2 more electrons to fill its outer shell, as it follows the octet rule to achieve stability.
All of them has one electron in their outer shell.