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In a neutral atom, the charge on the electron cloud is balanced by the carge on the atom's nucleus. The nucleus has a positive charge proportional to the number of protons in it. This attracts and holds the negatively charged electrons in the electron cloud. And in a neutral atom (not an ion), there will be as many electrons in the electron cloud as protons in the nucleus. The charges will balance.
The first ring of the electron cloud holds two electrons. All rings following it hold eight.
It is impossible to know exactly where an electron is. Thus, the size of an electron cloud can be given only in terms of probability. Even then, the size of the electron cloud depends on how many electrons an atom possesses.
Fluorine's atomic number is 9. Thus, fluorine has 9 protons and 9 electrons. As with every atom, all 9 of fluorine's electrons are found in the electron cloud.
Boron must give up 3 electrons in order to achieve a noble-gas electron configuration.
Boron has 5 electrons per atom. Boron's electron configuration is 1s2 2s2 2p1. Thus, it has 3 electrons in its outer shell.
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In a neutral atom, the charge on the electron cloud is balanced by the carge on the atom's nucleus. The nucleus has a positive charge proportional to the number of protons in it. This attracts and holds the negatively charged electrons in the electron cloud. And in a neutral atom (not an ion), there will be as many electrons in the electron cloud as protons in the nucleus. The charges will balance.
Boron has 2 orbitals
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None, electrons are in the electron cloud, not the nucleus
3, the electron configuration of Boron is 1s2 2s2 2p1, so there are 3 in the outer shell.
The first ring of the electron cloud holds two electrons. All rings following it hold eight.
Boron's atomic number is 5. Thus, its electron configuration is 1s2 2s2 2p1. If you add up the number of electrons in the "2" shell, which is boron's valence shell, you get 2 + 1 = 3 valence electrons.