Fluorine has 7 valence electrons. In order to become stable, Florine will share 1 electron with another atom to get 8 electron and become stable.
Just one. Fluorine has an outer shell of 2s2 2p5
Fluorine is in group vii. It takes oneelectron
One electron.
It isn't an atom, it would actually be a stable Fluorine Ion with a -1 charge.
Atoms become chemically neutral with either 2 or 8 electrons in the outermost orbital. Polonium would lose 2 electrons to become chemically neutral. Because Polonium is radioactive it will remain unstable until gains two in Atomic Number to resemble the configuration of Lead.
Neutral fluorine has an atomic number of 9, meaning it has 9 protons and 9 electrons. Trifluorine, were it to actually exist on its own, would be a molecule comprised of three fluorine atoms. Therefore, trifluorine would have 3 X 9 = 27 electrons per molecule.
The element that attracts electrons the most would be Fluorine
There are six electrons in two shells.In order to stable carbon, it take electrons from nearest noble gas to stable the carbon.It order to stable carbon it gain -4 electrons from the nearest noble gas Neon.
Fluorine will gain one electron to form F- (or fluoride) ion. Fluoride ion has a charge of -1.
Flourine is in Group XVII, which means that it has seven electrons in its outer shell. This means that it is only capable of forming single bonds.
An ionic bond takes place when one atom gives up an electron to another atom in order to have a stable valence. Whereas covalent bonds share electrons to sustain a stable valence. The Bohr diagram for Bismuth would be: Bi)2e-)8e-)18e-)32e-)18e-)5e- & Fluorine would be: F)2e-)7e- The valence for Bismuth has 5 electrons and Fluorine has 7 electrons, hence Bismuth requires 3 more electrons and Fluorine needs 1 more electron to become an octet. Therefore, to balance BiF3: for one Bismuth atom you will need 3 Fluorine atoms attached, both atoms will share the electrons to satisfy a complete octet in the valence for both atoms.
It'll have to lose two to have a stable octet.
It must gain 2 electrons to become stable then it would have a charge of -2 and be iso-electronic with Neon.
It isn't an atom, it would actually be a stable Fluorine Ion with a -1 charge.
Yes, definitely. It would form LiF, or Lithium fluoride. Lithium is a metal with 1 extra electron that it needs to lose to become stable and Fluorine is a nonmetal with 7 electrons so it needs to gain 1 more to fill its valence electron shell and complete its octet. Lithium loses its electron to Fluorine and this creates an ionic bond.
The nucleus would become unstable because you need a certain amount of neutrons, electrons, and protons for it to be stable.
Atoms become ions by gaining or losing electrons to achieve a noble gas configuration of electrons, which is stable. Argon already has such a configuration and is very stable as it is. Any gain or loss of electrons would make it less stable.
Oxygen has six valence electrons, which means that it needs to gain two to become stable. it takes much more energy for oxygen to lose its 6 valence electrons than it would be to gain 2. When atoms form compounds, they become stable.
Chemical Reactions would not exist, since unstable electrons are needed to start a Chemical Reaction, All the molecules would be stable, so they would not need to undergo change to become more stable.
It would have to lose two electrons.