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The formula for aluminum oxide is Al2O3, which means that, if aluminum oxide is ionically bonded, every formula mass of aluminum oxide contains three O-2 ions. In this instance, 0.65 formula masses of aluminum oxide would contain 3 X 0.65 or 1.95 moles of O2-. If aluminum oxide were covalently bonded, it would not contain any O-2 ions.
10.4 g NaF x 1 mol NaF/42 g x 1 mol F/mol NaF = 0.248 moles F- ions (3 significant figures).
0.00833 moles of CO3
8
3(2.6) = 7.8 moles of ions
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
The formula for aluminum oxide is Al2O3, which means that, if aluminum oxide is ionically bonded, every formula mass of aluminum oxide contains three O-2 ions. In this instance, 0.65 formula masses of aluminum oxide would contain 3 X 0.65 or 1.95 moles of O2-. If aluminum oxide were covalently bonded, it would not contain any O-2 ions.
Steps to take: Write the chemical formula : Al2O3 Calculate the number of moles for aluminum oxide. You should know the formula which is the mass given (0.051g) divided by the Mass of aluminum oxide. Since there is '2' moles of Aluminium you multiplly the number of moles calculated for aluminum oxide by 2. Then you have calculated the number of Ions.
there are 4.5 moles
2 ions
The individual ions for calcium fluoride have the formulas Ca+2 and F-1 respectively. That means that in any sample of calcium fluoride, there must be twice as many of the fluoride ions.
0.00833 moles of CO3
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
I suppose that the answers are: - 0,9 moles aluminium ions - 2,7 moles chloride ions
10.4 g NaF x 1 mol NaF/42 g x 1 mol F/mol NaF = 0.248 moles F- ions (3 significant figures).
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There are 2.8604 moles of ammonium ions in 6.955.