Either 1.999 OR 1.203398x1024
CaCO3 Molar Mass = 100.05g
200/105.05 = 1.999
1.999 x 6.02x1023
= 1.203398x1024
Not sure if wrong or...
The formula for calcium carbonate is CaCO3, and it has a gram formula mass of 100.09. The formula shows that each formula mass contains one calcium atom, which has a gram atomic mass of 40.08. Therefore, the mass fraction of calcium in calcium carbonate is 40.08/100.09, so that a 500 mg tablet of calcium carbonate contains 200 mg of calcium, to the justified number of significant digits.
Calcium has Wt 40, carbon is 12 and oxygen 16, so the MWt of calcium carbonate is 40+12+3x16=100. As this contains 40 calcium, calcium carbonate is 40% calcium. 40% of 418 is 167.2grams
1400 grams
mass of CaCO3 = 246 grams
mass of CaF3 = 61.96g mass of Al2CO3 =61.104 g
To find the number of moles in 200 grams of Calcium Carbonate, you need to divide the given mass by the molar mass of Calcium Carbonate. The molar mass of Calcium Carbonate (CaCO3) is 100.09 g/mol. So, 200 g / 100.09 g/mol = 1.999 moles of Calcium Carbonate.
To calculate the mass of calcium carbonate required to decompose and produce 4.4 grams of carbon dioxide, you need to first determine the molar mass of CaCO3 and CO2. Then, by using the stoichiometry of the reaction, you can calculate the amount of CaCO3 needed to produce 4.4 grams of CO2. The balanced reaction is: CaCO3 -> CaO + CO2.
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, 2.8 moles of calcium carbonate would be 280.25 grams.
The formula for calcium carbonate is CaCO3, and it has a gram formula mass of 100.09. The formula shows that each formula mass contains one calcium atom, which has a gram atomic mass of 40.08. Therefore, the mass fraction of calcium in calcium carbonate is 40.08/100.09, so that a 500 mg tablet of calcium carbonate contains 200 mg of calcium, to the justified number of significant digits.
There are 6 ions of carbonate present in 40 grams of calcium carbonate. This is because each molecule of calcium carbonate (CaCO3) contains one carbonate ion (CO3^2-) alongside one calcium ion (Ca^2+), giving a total of 2 ions per one molecule of calcium carbonate.
The mass of sodium bicarbonate (NaHCO3) is 84 grams/mol, while the mass of calcium carbonate (CaCO3) is 100 grams/mol. Therefore, calcium carbonate has a higher molecular mass compared to sodium bicarbonate.
Calcium has Wt 40, carbon is 12 and oxygen 16, so the MWt of calcium carbonate is 40+12+3x16=100. As this contains 40 calcium, calcium carbonate is 40% calcium. 40% of 418 is 167.2grams
1400 grams
The molar mass of calcium carbonate is 100.09 g/mol and the molar mass of hydrochloric acid is 36.46 g/mol. Using the mole ratio of the balanced chemical equation, you can calculate the amount of calcium carbonate that can be dissolved by 5.00 grams of hydrochloric acid, which is approximately 12.43 grams.
0.720940834 grams