5
The answer is 18,26 g CaCl2.
2,8 moles of calcium carbonate have 240,208 g.
9.03x10 23 ions
The answer is 19,288 g cacium carbonate.
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
The answer is 18,26 g CaCl2.
2,8 moles of calcium carbonate have 240,208 g.
6,863 grams of CaO
9.03x10 23 ions
1400 grams
Calcium has Wt 40, carbon is 12 and oxygen 16, so the MWt of calcium carbonate is 40+12+3x16=100. As this contains 40 calcium, calcium carbonate is 40% calcium. 40% of 418 is 167.2grams
0.720940834 grams
The answer is 19,288 g cacium carbonate.
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
My Shaft
caco3 (40)+(12)+3(16) =100/40 =2.5