As many as you like, depending on what you want the concentration to be. (Solubility will eventually become a factor, but sodium hydroxide is pretty darn soluble.)
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You need 40.01 g NaOH per liter volume of the solution. This is not the same as adding 1 liter of water to 40.01 g of NaOH. The NaOH must be put in the flask and the volume brought up to 1 liter total volume (NaOH volume + water volume).
It is possible only if you evaporate the water.
Simple equality will do here as you have three things and require a fourth. (X L)(2.5 M NaOH) = (2.0 L)(0.75 M NaOH) 2.5X = 1.5 X = 0.60 Liters needed ================
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
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You need 40.01 g NaOH per liter volume of the solution. This is not the same as adding 1 liter of water to 40.01 g of NaOH. The NaOH must be put in the flask and the volume brought up to 1 liter total volume (NaOH volume + water volume).
NaOH and H2O form a solution of Na+(aq) and OH-(aq) ions (the solvent water, aq, is written as subscripted (aq) ) To make 1 Normal solution you need to know the equivalent of NaOH, which is calculated by dividing Molecular weight by 1, that is 40 divided by 1= 40. So the equivalent weight of NaOH is 40. To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume of 1 liter.
It is possible only if you evaporate the water.
Take 60 gm NaOH (100%) disolve it in distilled water, and make up to 2.0 liter by distlilled water.the prepared solution is 0.75 N NaoH Solution.
Simple equality will do here as you have three things and require a fourth. (X L)(2.5 M NaOH) = (2.0 L)(0.75 M NaOH) 2.5X = 1.5 X = 0.60 Liters needed ================
a pH=10 solution of NaOH should contain 0,0001 moles of NaOH/liter. (1 mole/liter for pH=14, 0,1 for pH=13, etc.) A mole of NaOH is 40g-s. (Na=23g O=16g H=1g) 0,0001 mole is 0,004gs. You need the amount necessary for a quarter of a liter, so you divide by four. The result is that you need 0,001gs of NaOH. So if you need to make that solution without any precise laboratory equipment, you should make much larger quantities and just measure 0,250 l-s.
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution
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add 10 grams of NaoH into 1000 ml water, it will give you NaoH of 0.25N. As for making 1N solution you need to disolve 40 grams of NaoH into 1 litre water.
a solution of 0.1M NaOH has been prepared.How would you make 1L of the same solution