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a mole of gold weighs 197 grams and there are just over 6E23 atoms in a mole......... that's all you need to know........ now you compute it yourself!
Your answer will be correct to at least 2 digits... which is all anyone usually cares about anyway.
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∙ 10y ago
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What has the most atoms one mole of gold helium or lead?
1 mole atoms of all atoms of any element will always have the same number of atoms and will be equal to 6.023 x 1023 atoms. However the weight will vary. 1 mole = 4 g of Helium or 197 g of gold or 207 g of lead
How many atoms are there in 42.0000 g of Au?
The gram atomic mass of Au is 196.967. Therefore, 42.0000 g contains 42.0000/196.92 or 0.213234 gram atoms of gold. The number of atoms is 0.213234 X Avogadro's Number or 1.28412 X 1023 atoms.
How many atoms are there in 30.4 g of selenium?
78.96 g of selenium will have 6.023 x 1023 atoms. So, 30.4 g of selenium will have 2.32 x 1023 atoms.
How many uranium atoms are there in 6.2 g of pure uranium?
156,86.1020 atoms of uranium in 6,2 g uranium
How many atoms of sulfur (S) are in 5 g of sulfur?
5 g of sulfur contain 0,94.10e23 atoms.
How many atoms are in 2.3 g of gold?
390cm²
How many atoms of gold are in 0.02 g of Au?
6.14x1019 atoms Au
What mass of gold contains twice as many atoms as 2.74g of silver?
The gram atomic mass of silver is 107.868 and that of gold is 196.967. Equal numbers of gram atoms of different elements contain equal numbers of atoms. Therefore, the mass of gold required to contain twice as many atoms as 2.74 g of gold is (2 X 2.74 X 196.967)/107.868 or 10.0 g of gold, to the justified number of significant digits.
How many number of atoms is in 3.50g gold?
The formula unit for gold is a single atom, and the atomic weight of gold is about 197. Therefore, the number of atoms in 3.50 g of gold is Avogadro's Number X (3.50/197) or about 1.84 X 1022.
What has the most atoms one mole of gold helium or lead?
1 mole atoms of all atoms of any element will always have the same number of atoms and will be equal to 6.023 x 1023 atoms. However the weight will vary. 1 mole = 4 g of Helium or 197 g of gold or 207 g of lead
How many atoms are there in 42.0000 g of Au?
The gram atomic mass of Au is 196.967. Therefore, 42.0000 g contains 42.0000/196.92 or 0.213234 gram atoms of gold. The number of atoms is 0.213234 X Avogadro's Number or 1.28412 X 1023 atoms.
How many atoms of gold are in a necklace that weighs 12.7g?
12.7 g gold (1 mole Au/197.0 grams)(6.022 X 10^23/1 mole Au) = 3.88 X 10^22 atoms of gold
How many atoms are in .23 g Pb?
The number of atoms of lead is 6,68.10e23.
How many atoms are in 3.50 g of gold?
1 mole of gold is 196.97 grams. 7.2 mol Au * (196.97 g Au/1 mol Au) = 1418.18 g There are 1418.18 grams in 7.2 moles of gold.
A sample of gold has a mass of 5.00 x 10-3g. what amount of gold in atoms does the sample contain?
5x10-3 g divided by m.wt. of gold (197 g/mol) equals 2.5x10-5 mol gold.2.5x10-5 mol gold multiplied by Avogadro's Number (6.023x10+23 atoms/mol) equals 1.5x10+20 atoms.
How many atoms are in 1 gram of gold?
---- Golds molecular weight is 196.96 g/mol Thus, 1g of gold is (1g /196.96 g/mol) = 0.005 mol ---- 1 mol is 6.022 × 1023 atoms (Avogadro's Number) Thus, 0.005 mol is (0.005 mol x 6.022 × 1023 atoms/mol) = 3.057 x 1021 atoms ---- Therefore 1g of gold has APPROXIMATELY 3.057 x 1021 atoms
How many atoms are in 49.1740 g of zirconium?
49.1740 g (6.02 x 1023 atoms) / (91.22 g) = 3.25 x 1023 atoms
