What is the mass of 1.5 moles of MgCl2?

Answer 1

The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.
Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl2

1.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)

Answer 2

First realize that it takes 3 CL2 to produce one mole of CHCl3. So take

1.50 moles of CHCl3 * 3 moles of Cl2 / 1 mole of CHCL3= 4.5 mole of Cl2

The the atomic weight of Cl2 is 35.5*2=71g.

4.5 mole of Cl2*71g= 319.5g. of Cl2 needed.

Answer 3

The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.
Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl2

1.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)

Answer 4

The formula given shows that there are two atoms in each molecule. Therefore, the answer is 2 X 1.5 X Avogadro's Number = about 1.8 X 1024.

Answer 5

1.75 mole CHCl3 (6.02 X 10^23 mole CHCl3)

= 1.05 X 1024 atoms of CHCl3

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Answer 6

The number is 9,033.10e23 molecules.

Answer 7

The reaction is:
H2 + Cl2 = 2 HCl
The answer is 0,21 mol hydrogen.

Answer 8

Mg = 24.3Cl = 35.5 x 2 = 71

Total = 71 + 24.3 = 95.3 g = 1 moles MgCl2

1.5 moles x 95.3 g/mole = 143 grams

Answer 9

The mass of 1,5 moles of anhydrous MgCl2 is 142,82 g.

Answer 10

54 grams

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