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Q: How many grams are in 0.0751 mol Br2?
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How do you calculate the number of moles of bromine present in 16.0ml of Br2 whose density is 3.12gml?

First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.


How many atoms are in 1.54 moles of Bromine?

1.54 (mol Br2) * 6.022*10+23 (molecule/mol Br2) * 2 (atoms Br/molecule Br2) =1.85*1024 atoms in 1.54 mole Br2


What is the mass of 4.89 x 1020 molecules of Br2?

1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2 4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2


How many grams are in strontium chloride?

SrCl2 Strontium (Sr) = 87.62 grams/mol 2 Chlorine (Cl) = 70.9 grams/mol ----------------------------------------------------add Strontium chloride = 158.52 grams/mol ============================


How many grams in 4.23 m mol of HBr?

The answer is 0,3422 grams.


How many grams of co2 are in 2l mol of the compound?

92.4 grams


How many grams of ccl4 are needed to have 5.000 mol?

769.0 grams


How many moles of potassium bromide can be produced from the reaction of 2.92 moles of potassium with 1.78 moles of bromine gas?

First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr


How many grams are 3 mol of KBr?

357


How many grams in 1.6 mol NaCl?

As the molar mass of NaCl is 58.5 g/mol, 1.6 moles weight is 93.6 grams.


Are the number of atoms of bromine in 1 mol Br2 equal to avogadro's number?

No the number of ATOMS in 1 Bomine MOLECULE Br2 is twice Avagadro's number.


How many grams is 0.894 mol?

This depends on the chemical compound.