molec weight is 151g/mol.
1.11 moles x 151g/mol is 167.61g
Moles is mass / molecular mass
1,11 moles of anhydrous manganese sulfate contain 167,61 g.
Multiple the moles of K2SO4 by the molecular weight of 174.2592 grams. That should equal 210.85 grams.
FeCl3 ? 1.1 grams FeCl3 (1 mole FeCl3/162.2 grams) = 0.0068 moles of FeCl3 ------------------------------------
Not many! 5.0 grams CaBr2 (1 mole/199.88 grams CaBr2) = 0.025 moles CaBr2
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams454 grams CO2 / (44.0 grams) = 10.3 moles CO2
For this you need the atomic mass of Au. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.355 grams Au / (197.0 grams) = 1.80 moles Au
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
211 is the mass in grams of 1.15 moles of strontium sulfate.
4,0 moles of the manganese contain 219,75 g.
4,0 moles of the manganese contain 219,75 g.
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
You have to use the equationnumber of moles = mass/Molar massn = 5/(39.1+32.1+64)n = 5/135.2number of moles = 0.04:)
You need the molar solution to get the number of moles present in 6.52g of Zinc Sulfate.
1.5 moles
Calcium sulfate has chemical formula CaSO4. The formula mass is 40.1+32.1+4(16.0) = 136.2Mass of 2mol of CaSO4 = 2 x 136.2 = 272.4gThere are 272.4 grams of calcium sulfate in a two mole sample.
Sodium Sulfate is Na2SO4 and the molecular weight is 142. So 0.15 moles would have a mass of 0.15 x142 = 21.3g.
44.1-44.5 -Apex