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The weight of 2,5 mol of sulfuric acid is 245,1975 g.
Wiki User
∙ 8y ago
Wiki User
∙ 14y agomoles=mass/Molar Mass 6.50=mass/98 mass=637g 6.5 moles of H2SO4 weighs 637g.
Wiki User
∙ 10y ago0.05 moles H2SO4 (98.086 grams/1 mole H2SO4)
= 4.9 grams sulfuric acid
================( could call it 5.0 grams )
Wiki User
∙ 14y ago49.045g
Wiki User
∙ 11y ago49.038
Lakeithon Hardeman
26 grams
Johnnyboy
49.1g
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How many milliliters of 3.0 m h2so4 are required to react with 0.80 g of cuo in the equation cuo h2so4 cuso4 H2O?
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
How many moles are present in 1g of H2So4?
0.010 moles The molar mass of H2SO4 is 98.1 grams per mole. To find out how many moles are present in a given mass, divide the mass by the molar mass. So: 1g/98.1g mol-1 is 0.010 mol.
How many grams are in 2.5 moles of sulfuric acid?
The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.
What is the mass of 4.09 mol of H2SO4?
The molar mass of sulfuric acid is 98.08 grams per mole. 4.09 x 98.09 = 401.1881 grams.
How do you do the atiomic mass of h2so4?
Per mole H2SO4.Two hydrogens; 2 * 1.008 g/mol = 2.016One sulfur; 1 * 32.07 g/mol = 32.07Four oxygen; 4 * 16/g/mol = 64--------------------------------------------------------add the bold= 98.086 grams/mole========================Sulfuric acid
How many grams of ammonia are presented in 5.0 l of a 0.050 m solution?
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
How many grams of sulfuric acid are needed to react with 8 mol of ammonium hydroxide?
2NH4OH + H2SO4 >> (NH4)2SO4 + 2H2O 8 moles NH4OH (1mol H2SO4/2mol NH4OH)(98.086g H2SO4/1mol H2SO4) = 392.34 grams H2SO4 needed
What is molecular mass of h2so4?
The mass in grams of one mole H2SO4 is: 98.079 g/mol (molar mass)The mass in grams of one molecule H2SO4 is (molecule mass):98.079 (g/mol) / 6.02214*10+23(molecules/mol) = 16.286*10-23 g/molecule
How many grams of HCl can be prepared from 2.00 mol H2SO4 and 150 g NaCl?
Try asking Google
How many milliliters of 3.0 m h2so4 are required to react with 0.80 g of cuo in the equation cuo h2so4 cuso4 H2O?
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
How many moles are present in 1g of H2So4?
0.010 moles The molar mass of H2SO4 is 98.1 grams per mole. To find out how many moles are present in a given mass, divide the mass by the molar mass. So: 1g/98.1g mol-1 is 0.010 mol.
How many grams are in 2.5 moles of sulfuric acid?
The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.
How many grams of HCl can be prepared from 2.00 mol H2So4 and 150 g NaCl?
2NaCl + H2SO4 ----> 2HCl + Na2SO4 *molar mass of H2SO4 is 98.09g *molar mass of NaCl is 58.44g *molar mass HCl is is 36.46g Moles NaCl = 150 g / 58.44 = 2.56 The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
What is the mass of 4.09 mol of H2SO4?
The molar mass of sulfuric acid is 98.08 grams per mole. 4.09 x 98.09 = 401.1881 grams.
How do you do the atiomic mass of h2so4?
Per mole H2SO4.Two hydrogens; 2 * 1.008 g/mol = 2.016One sulfur; 1 * 32.07 g/mol = 32.07Four oxygen; 4 * 16/g/mol = 64--------------------------------------------------------add the bold= 98.086 grams/mole========================Sulfuric acid
How do you prepare an aqueous 3.0 M solution H2SO4 from crystal H2SO4?
Start with 1 dm^3 (1 Liter) of pure H2O. Molarity is defined as Mol/dm^3, so this is generally an easy way to go. Measure out 3 mol of H2SO4 -> First find the molar weight of Sulfuric acid, which is, according to Google: 98.079g/mol. So 3 mol * 98.079g/mol = 294.24 grams of H2SO4. Add that to 1 Liter of water, and you'll have an aqueous 3 Molar solution!
How many moles are there in 22.4 g of H2SO4?
22.4g/98.09 g/mol = 0.228mol
