278
5.00 g
1
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
avagadro number
0,15 moles NaOH contain 6 g.
The atomic mass of sodium, Na is 23.0 Amount of sodium = mass of sample / atomic mass = 120/23.0 = 5.22mol
1
155.2 g
0.2 mol
The iron(III) hydroxide is not soluble in water and doesn't react with sodium chloride.
The molecular weight of sodium hydroxide is 40. Therefore 0.150 moles would be 40 x 0.15 = 6g.
To find the amount of sodium hydroxide needed to react with 150g of phosphoric acid, you first need to determine the balanced chemical equation between sodium hydroxide and phosphoric acid. From there, you can use stoichiometry to calculate the amount of sodium hydroxide needed.
98g
avagadro number
262 - 266
262 - 266
The balanced chemical equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl) is 1 mol NaOH : 1 mol HCl. Calculate the amount of NaOH required by converting the given mass of HCl to moles using its molar mass, then use the mole ratio from the balanced equation to determine the moles of NaOH needed, and finally convert moles of NaOH to grams using its molar mass.
0,15 moles NaOH contain 6 g.