2.430g. That's one tenth the number of grams in one mole of Mg, which would be 24.30, which is also its atomic weight. No, that is not a coincidence. Atomic weight of an element is always equal to the number of grams of an element in a mole of the same element.
0,100 mol of C2H5OH is equal to 4,607 grams.
800 g oxygen are needed.
16g
1 kilogram = 1000 grams. You now have all the information required to work out, for yourself, the answer to this and similar questions.
1 cup = 226,79 grams / 226,79 grams = 1 cup
C3H8 + 5O2 --> 3CO2 + 4H2O 2.75 mole C3H8 (5 moles O2/1 mole C3H8)(32 grams/1 moleO2) = 440 grams oxygen required =====================
For this you need the atomic (molecular) mass of C2H5OH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. C2H5OH= 46.1 grams1.271 grams C2H5OH / (46.1 grams) = .0276 moles C2H5OH
14.7 g
Seven!
63.3 g
2
hi
how many grams of hydrogen are required to completely saturate 75 grams oleic acid which has one double bond ?
The mass of 2 moles of ethyl alcohol would be 92,14 grams.
3 grams
Seventeen
30 grams
7.64 days