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Q: How many grams do 5.8 x 1021 atoms of hydrogen weigh?
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How many moles are there in 8.93 1021 atoms?

8.93 1021 atoms equal 0,0148 moles.


How many atoms are present in 5 grams of AuCl3?

For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AuCl3= 303.5 grams5.00 grams AuCl3 / (303.5 grams) × (6.02 × 1023 atoms) = 9.92 × 1021 atoms


How many carbon atoms are present in 0.5 carat?

0.5 carat carbon (0.2 grams/1 carat)(1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 5.0 X 1021 atoms of carbon ===================


What is the mass of 3.01.1021 atoms of nitrogen?

(3.66) There's 2 N and there are 14.00674 atoms so multiple 14.00674 by 2 and you get 28.0138. (3.66)(28.0138/1) = 102.53


How many atom in 1g of molybdenum?

1 gram molybdenum (1 mole Mo/95.94 grams)(6.022 X 1023/1 mole Mo) = 6 X 1021 atoms of molybdenum ========================


How many moles are in 4.3 x 1021 molecules of UF6?

A mole is a unit of measurement that is used to measure the number of things. The amount of moles that are in 4.3 x 1021 molecules of UF6 are 9.34 and the amount of grams is 2.51.


How many tons does Venus's weigh?

The mass of Venus is 5.36660262 x 1021 tons.


How many atoms are in 0.7 grams of Helium?

.7 g= .17 mol = 1.05 x 10^23 atoms


How much does the asteroid weigh?

3.0 to 3.6x 1021 kilograms which i 4 percent of earth's moon


How many carbon atoms are there in a diamond with a mass of 52mg?

A diamond is pure carbon, less subtle impurities, so..., 55 mg (1 gram/1000 mg)(1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 2.6 X 1021 atoms of carbon ==================


How much does haumea weigh?

Haumea weighs (4.006 ± 0.040) x 1021 kg, or about 0.00066 Earths.


How of atoms are in 1.80 mL of mercury?

A complete answer would require specification of a temperature, but at 20C, mercury is reported to have a density of 13.5939 grams per milliliter, so that 1.80 mL would have a mass of 1.80 X 13.5939 or 245 grams, to the justified number of significant digits. The gram atomic mass, which is the mass of Avogadro's number of mercury atoms, is 200.6; and Avogadro's Number is about 6.022 X 1023. Therefore the number of atoms in the volume specified is (245/200.6)(6.022) X 1023 or 7.345 X 1021 atoms.