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0.5 carat carbon (0.2 grams/1 carat)(1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 5.0 X 1021 atoms of carbon ===================
(3.66) There's 2 N and there are 14.00674 atoms so multiple 14.00674 by 2 and you get 28.0138. (3.66)(28.0138/1) = 102.53
The mass of Venus is 5.36660262 x 1021 tons.
.7 g= .17 mol = 1.05 x 10^23 atoms
Haumea weighs (4.006 ± 0.040) x 1021 kg, or about 0.00066 Earths.
8.93 1021 atoms equal 0,0148 moles.
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AuCl3= 303.5 grams5.00 grams AuCl3 / (303.5 grams) × (6.02 × 1023 atoms) = 9.92 × 1021 atoms
0.5 carat carbon (0.2 grams/1 carat)(1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 5.0 X 1021 atoms of carbon ===================
(3.66) There's 2 N and there are 14.00674 atoms so multiple 14.00674 by 2 and you get 28.0138. (3.66)(28.0138/1) = 102.53
1 gram molybdenum (1 mole Mo/95.94 grams)(6.022 X 1023/1 mole Mo) = 6 X 1021 atoms of molybdenum ========================
A mole is a unit of measurement that is used to measure the number of things. The amount of moles that are in 4.3 x 1021 molecules of UF6 are 9.34 and the amount of grams is 2.51.
The mass of Venus is 5.36660262 x 1021 tons.
.7 g= .17 mol = 1.05 x 10^23 atoms
3.0 to 3.6x 1021 kilograms which i 4 percent of earth's moon
A diamond is pure carbon, less subtle impurities, so..., 55 mg (1 gram/1000 mg)(1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 2.6 X 1021 atoms of carbon ==================
Haumea weighs (4.006 ± 0.040) x 1021 kg, or about 0.00066 Earths.
A complete answer would require specification of a temperature, but at 20C, mercury is reported to have a density of 13.5939 grams per milliliter, so that 1.80 mL would have a mass of 1.80 X 13.5939 or 245 grams, to the justified number of significant digits. The gram atomic mass, which is the mass of Avogadro's number of mercury atoms, is 200.6; and Avogadro's Number is about 6.022 X 1023. Therefore the number of atoms in the volume specified is (245/200.6)(6.022) X 1023 or 7.345 X 1021 atoms.