0
What else can I help you with?
How many moles are there in 9g of Al show working?
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
What is 3.56 mol Al in grams?
3,56 mol Al is equal to 96,05 grams.
How many atoms of oxygen are there in 698 grams of AlNo33?
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
2.91 moles of aluminum are how many grams?
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.91 moles Al × (27.0 grams) = 78.6 grams Al
What is the mass in grams for 4.5 moles of aluminum?
2.38 mol Al
How many moles are there in 9g of Al show working?
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
What is flax seed in Arabic?
بذر الكتان, حبْ الكتّان Habba Al-Kattan or Bazra Al-Kattan
What is 3.56 mol Al in grams?
3,56 mol Al is equal to 96,05 grams.
How many grams of aluminum are in 0.471 moles of aluminum please show your work?
The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g
How many grams Al from 0.4 moles AlCl3?
The mass of aluminium is 11,2 g.
How many moles of aluminum are in 10grams of aluminum?
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
How many atoms of oxygen are there in 698 grams of AlNo33?
Quite a few! 698 grams Al(NO3)3 (1 mole Al(NO3)3/213.01 grams)(9 moles O/1 mole Al(NO3)3)(6.022 X 1023/1 mole O) = 1.78 X 1025 atoms of oxygen ======================
What is the mass in grams of 1.00 mol Al?
7 X 102 g Al this is the awnser using significant figures
How many grams of alcohol does bud light have?
Answer 14.2884 Grams 12 fluid oz. 4.2 % AL There are 28.35 grams in one ounce x 12 = 340.2 grams 340.2 x .042 = 14.2884 grams Roughly a 1/2 ounce
If 76 grams of Cr 2 O 3 and 27 grams of Al react to form 51 grams of Al 2 O 3 how many grams of Cr are formed?
To find the mass of Cr formed, we first need to calculate the initial moles of Cr2O3 and Al. Next, we determine the limiting reactant based on stoichiometry. Knowing Al is the limiting reactant, we calculate the theoretical yield of Al2O3 formed, and then find the amount of Cr formed based on the stoichiometry of the reaction.
How many moles are in one gram of Al?
For this you need the atomic mass of Al. Take the number of grams and divide it by the atomic mass. Multiply it by one mole for units to cancel.94.5 grams Al / (27.0 grams) = 3.50 moles Al
What is the maximum amount of Cu that could be produced by reacting 20.0 grams of Al with excess CuSO4?
find moles: 20.0 grams of Al @ (27.0 g/mol) = 0.7407 moles of Al by the reaction: 2 moles Al+3CuSO4 → Al2(SO4)3 +3 moles Cu 0.7407 moles of Al produces 3/2 's as many moles of Cu = 1.11 moles of Cu find mass, using molar mass: 1.11 moles of Cu @ (63.5 g/mol) = 70.6 grams of Cu your answer is 70.6 g
