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For this you need the Atomic Mass of Al. Take the number of grams and divide it by the atomic mass. Multiply it by one mole for units to cancel.
94.5 grams Al / (27.0 grams) = 3.50 moles Al
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∙ 15y ago
Approximately 0.037 moles are in one gram of Aluminum (Al), using the molar mass of Al (approximately 27 g/mol).
Wiki User
∙ 11y agoThere are 26.98 gram in 1 mole Al, so it is 1/26.98 = 0.03706 mole per gram Aluminum
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∙ 11y ago1 mole of Al is equal to about 27 grams (Periodic Table).
Use this as a conversion factor.
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∙ 8y ago4,25 moles of aluminium is equivalent to 114,67 g.
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∙ 7y agomoles of Al = 97.6 g Al x 1 mol Al/26.98 g Al = 3.62 moles Al (3 sig figs)
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∙ 13y ago1/27 = 0.037
Wiki User
∙ 11y agoThe answer is 0,07 moles.
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How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?
2 moles of Al react with 6 moles of HCl to produce 2 moles of AlCl3. The molar mass of Al is 27 g/mol and AlCl3 is 133.34 g/mol. So, 18 g of Al produces 18/27 = 0.67 moles of Al, which reacts to produce 0.67 moles of AlCl3. So, 0.67 moles of AlCl3 is 0.67 * 133.34 = 89.33 grams of AlCl3.
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
How many moles of aluminum oxide can be made if 4.0 moles Al completely react?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O₂) to form aluminum oxide (Al₂O₃) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Al₂O₃). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
How many moles of O2 must react with 5 moles of Al?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O2) is 4 Al + 3 O2 → 2 Al2O3. This means that 3 moles of O2 react with 4 moles of Al. Therefore, to react with 5 moles of Al, you would need (5 moles Al) x (3 moles O2 / 4 moles Al) = 3.75 moles of O2.
How many moles of aluminum oxide can be made if 5.23 mol Al completely react?
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
How many atoms are in one gram of 13Al?
1mol Al = 26.981538g Al1mol Al atoms = 6.022 x 1023 atomsConvert grams to moles.1g Al x 1mol/26.981538g = 0.04mol AlConvert moles to atoms.0.04mol Al x 6.022 x 1023 atoms/mol = 2 x 1022 atoms Al
How many moles of H2 can you get from 4 moles of Al?
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
How many moles of HCl and needed to react 2.4 moles of Al?
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?
2 moles of Al react with 6 moles of HCl to produce 2 moles of AlCl3. The molar mass of Al is 27 g/mol and AlCl3 is 133.34 g/mol. So, 18 g of Al produces 18/27 = 0.67 moles of Al, which reacts to produce 0.67 moles of AlCl3. So, 0.67 moles of AlCl3 is 0.67 * 133.34 = 89.33 grams of AlCl3.
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
How many moles of oxygen must react with 4.50 mol Al?
The answer is 3,375 moles oxygen.
How many moles of aluminum oxide can be made if 4.0 moles Al completely react?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O₂) to form aluminum oxide (Al₂O₃) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Al₂O₃). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
How many moles of O2 must react with 5 moles of Al?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O2) is 4 Al + 3 O2 → 2 Al2O3. This means that 3 moles of O2 react with 4 moles of Al. Therefore, to react with 5 moles of Al, you would need (5 moles Al) x (3 moles O2 / 4 moles Al) = 3.75 moles of O2.
How many moles of H2SO4 will react with 18mol of Al?
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
How many moles are there in 9g of Al show working?
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
How many moles of aluminum oxide can be made if 5.23 mol Al completely react?
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
In the reaction of aluminum metal and oxygen gas aluminum oxide is formed How many moles of O2 will react with 2.0 moles Al?
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
