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For this you need the Atomic Mass of Al. Take the number of grams and divide it by the atomic mass. Multiply it by one mole for units to cancel.
94.5 grams Al / (27.0 grams) = 3.50 moles Al
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How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?
2 moles of Al react with 6 moles of HCl to produce 2 moles of AlCl3. The molar mass of Al is 27 g/mol and AlCl3 is 133.34 g/mol. So, 18 g of Al produces 18/27 = 0.67 moles of Al, which reacts to produce 0.67 moles of AlCl3. So, 0.67 moles of AlCl3 is 0.67 * 133.34 = 89.33 grams of AlCl3.
How many moles of aluminum oxide (Al2O3) are formed in the reaction Fe2O3 plus 2Al and rarr Al2O3 plus 2Fe?
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
How many moles of O2 must react with 5 moles of Al?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O2) is 4 Al + 3 O2 → 2 Al2O3. This means that 3 moles of O2 react with 4 moles of Al. Therefore, to react with 5 moles of Al, you would need (5 moles Al) x (3 moles O2 / 4 moles Al) = 3.75 moles of O2.
How many moles of aluminum oxide can be made if 4.0 moles Al completely react?
If aluminum reacts completely with oxygen to form aluminum oxide, then 4.0 moles of aluminum will react to form 4.0 moles of aluminum oxide. Each mole of aluminum reacts with one mole of oxygen to form one mole of aluminum oxide.
How many moles of aluminum oxide can be made if 5.23 mol Al completely react?
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
