3,56 mol Al is equal to 96,05 grams.
2.38 mol Al
As the periodic table of Elements states, Al has a Molar Mass (Grams/Mole) of 27.0g/mol. So 3 mols of Al mass is the same as 3 times 27.0g/mol. So, the equation is as follows: 3mols x 27.0g/mol = 81.0g. The reason on why it ends with grams is because the unit of moles in 3 will cancel out with the unit of mols in 27.0g.
To convert grams of aluminum to moles, you need to divide the given mass (5 g) by the molar mass of aluminum (26.98 g/mol). Therefore, 5 g of aluminum is equal to 5/26.98 = 0.185 moles of aluminum.
There are approximately 12.56 ounces in 356 grams.
356g = 12.56oz
7 X 102 g Al this is the awnser using significant figures
The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g The molar weight of aluminum (Al) is 26.98 g/mol. grams of Al = 26.98 x 0.471 = 12.71 g
2.38 mol Al
356 grams is about 0.7848 pounds.
As the periodic table of Elements states, Al has a Molar Mass (Grams/Mole) of 27.0g/mol. So 3 mols of Al mass is the same as 3 times 27.0g/mol. So, the equation is as follows: 3mols x 27.0g/mol = 81.0g. The reason on why it ends with grams is because the unit of moles in 3 will cancel out with the unit of mols in 27.0g.
To calculate the energy absorbed, first convert the mass of ethanol from grams to moles. 356 g of ethanol is 356/46.0 = 7.74 moles. Then, multiply the moles of ethanol by the heat of vaporization: 7.74 mol * 38.6 kJ/mol = 298.56 kJ of energy absorbed.
To convert grams of aluminum to moles, you need to divide the given mass (5 g) by the molar mass of aluminum (26.98 g/mol). Therefore, 5 g of aluminum is equal to 5/26.98 = 0.185 moles of aluminum.
There are approximately 12.56 ounces in 356 grams.
Convert 62.13 kg Al to grams.62.13 kg (1000 g/kg) = 62130 g AlConvert grams to moles using the atomic weight of Al from the periodic table.Al is 26.9815 g/mol62130 g / (26.9815 g/mol) = 2302.6 mol AlIn significant figures, that is 2303 mol Al.In scientific notation, that is 2.303 x 104 mol Al.
356g = 12.56oz
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.00 moles Al × (27.0 grams) = 54.0 grams Al
To find the grams of solute needed, use the formula: [ \text{grams} = \text{molarity (M)} \times \text{volume (L)} \times \text{molar mass (g/mol)}. ] The molar mass of Al(NO₃)₃ is approximately 213.00 g/mol. For a 3.0 M solution in 2.5 L: [ \text{grams} = 3.0 , \text{mol/L} \times 2.5 , \text{L} \times 213.00 , \text{g/mol} = 1597.5 , \text{g}. ] Thus, you would need approximately 1597.5 grams of Al(NO₃)₃.