For this you need the Atomic Mass of S. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.
2.4 mole S × (32.1 grams) = 77.0 grams S
1.20400 X 10^24
You multiply 2 (because there are 2 moles of sulfur) by Avogadro's Number.
2,6 moles of sulfur are equal to 83,356 g.
2,0 moles of a sample of sulfur is equal to 64,12 g.
Assuming you are talking about pure sulfer. Atomic weight of Sulfer is : 32.07g/mol 100g / 32.07 g/mol = 3.06 mol (rounded to nearest 2 decimal place) 1 mol = 6.022 141 79 × 1023 atoms. 3.06 X 6.022 141 79 × 1023 = 1.82 X 10^24 atoms
The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol. Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37% Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147% Mass of Sulfur = 32.06g/mol Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49% 42.37% + 9.147% + 48.49% = 100.00%
1.54 (mol Br2) * 6.022*10+23 (molecule/mol Br2) * 2 (atoms Br/molecule Br2) =1.85*1024 atoms in 1.54 mole Br2
18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.
1 molecule of hydrogen contains 2 hydrogen atoms,so 1 mole of hydrogen consists of 2 moles of atoms.
Assuming you are talking about pure sulfer. Atomic weight of Sulfer is : 32.07g/mol 100g / 32.07 g/mol = 3.06 mol (rounded to nearest 2 decimal place) 1 mol = 6.022 141 79 × 1023 atoms. 3.06 X 6.022 141 79 × 1023 = 1.82 X 10^24 atoms
2 Sulfur atoms and 3 Oxygen atoms
1 sulfur atom 2 oxygen atoms
The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol. Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37% Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147% Mass of Sulfur = 32.06g/mol Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49% 42.37% + 9.147% + 48.49% = 100.00%
The number of atoms is 12, 044 280 171 4.10e23.
2(6.02 x 10^23) atoms
1
A sulfur molecule is 2 sulfur atoms covalently bonded. A sulfur dioxide molecule is a sulfur atom and 2 oxygen atoms covalently bonded.
3.0 g Fe x 1 mole Fe/55.8 g = 0.054 moles Fe2.0 g S x 1 mole S/32 g = 0.063 moles STherefore there are more molecules of S than of Fe since one mole of either = 6.02x10^23 atoms.
1.54 (mol Br2) * 6.022*10+23 (molecule/mol Br2) * 2 (atoms Br/molecule Br2) =1.85*1024 atoms in 1.54 mole Br2
18 mol of NH3 (ammonia) contains 18 mol of N atoms. 1 mole of N2 (nitrogen gas) contains 2 mol N atoms. so 9 mol N2 is used to produce 18 mol NH3.
1 molecule of hydrogen contains 2 hydrogen atoms,so 1 mole of hydrogen consists of 2 moles of atoms.