24 / 40 = x / 4.00 x = 2.4 g Mg
340 grams
13.5g Mg(NO3)2 x 1 mol Mg(NO3)2/148.3 = 0.0910 mol Mg(NO3)2
160 grams MgO (1 mole MgO/40.31 grams) = 3.97 mole magnesium oxide =====================
8 g of magnesium chloride is obtained.
i dont know help :C
Theoretically the mass is 62,3018 g.
1,11 moles of magnesium have 26,97855 g.
There are 0.13 moles in 20 grams of magnesium nitrate.
88,1 moles of magnesium is equivalent to 2 141,27 g.
2
24 / 40 = x / 4.00 x = 2.4 g Mg
A lot
340 grams
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
Magnesium chloride: 81,95 g are obtained.
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g