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The Atomic Mass of magnesium (Mg) is approximately 24.305 grams per mole.
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How many grams of magnesium would be required to produce 4.00 grams of magnesium oxide?
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many grams of magnesium oxide and oxygen react to form 20.0 grams of magnesium oxide?
To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.
In the reaction between magnesium and oxygen the mass of magnesium and oxygen was 2.5 grams how much magnesium oxide was formed?
The molar mass of magnesium is 24.3 g/mol and oxygen is 16 g/mol. The balanced equation is 2Mg + O2 -> 2MgO. Since magnesium and oxygen react in a 1:1 ratio, all magnesium reacted to form magnesium oxide. Therefore, 2.5 grams of magnesium oxide was formed.
Can you calculate the number of moles of magnesium used grams permol?
To calculate the number of moles of magnesium used, you divide the mass of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 g/mol. For example, if you have 12.15 grams of magnesium, you would divide 12.15 by 24.31 to find that you have 0.5 moles of magnesium.
How many grams of magnesium would be required to produce 4.00 grams of magnesium oxide?
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
How many grams of magnesium fluoride would you produce if you added 24 grams of magnesium to 38 grams of fluorine?
Theoretically the mass is 62,3018 g.
There are 3 grams of magnesium and 2 grams of oxygen if 4 grams of magnesium oxide is produced and all of the magnesium was used up how many grams of oxygen are left?
If 3 grams of magnesium are used to form 4 grams of magnesium oxide, then 1 gram of oxygen is used in the reaction. This means 1 gram of oxygen remains unused.
How many grams are in 1.11 moles of magnesium?
1,11 moles of magnesium have 26,97855 g.
How many moles in 20g of magnesium nitrate?
There are 0.13 moles in 20 grams of magnesium nitrate.
How many grams of magnesium nitride can be made from 55.3 grams of magnesium if all the magnesium reacts only with nitrogen?
Balanced equation first. 3Mg + N2 -> Mg3N2 55.3 grams Mg (1 mole Mg/24.31 grams)(1 mole Mg3N2/3 mole Mg)(100.95 grams/1 mole Mg3N2) = 76.5 grams Mg3N2 made ===================
How many moles are in 88.1 grams of magnesium?
88,1 moles of magnesium is equivalent to 2 141,27 g.
There are 6 grams of magnesium and 4 grams of oxygen if 8 grams of magnesium oxide is produced?
2
How many grams of water are needed to produce one hundred fifty grams of magnesium hydroxide?
A lot
How many moles in 13.5 grams of magnesium nitrate?
To find the number of moles in 13.5 grams of magnesium nitrate, you need to divide the given mass by the molar mass of magnesium nitrate. The molar mass of magnesium nitrate (Mg(NO3)2) is 148.31 g/mol. Moles of magnesium nitrate = 13.5 grams / 148.31 g/mol ≈ 0.091 moles
How many grams of magnesium oxide and oxygen react to form 20.0 grams of magnesium oxide?
To determine the amount of oxygen, we first find the amount of magnesium by subtracting the given 20.0 grams of magnesium oxide from the total. Given that the molar mass of magnesium oxide is 40.3 g/mol and that of magnesium is 24.3 g/mol, we calculate the amount of oxygen by adjusting accordingly. This process gives us the weight ratio of magnesium oxide to oxygen.
How many grams are in 5.2 moles of magnesium sulfide?
Mass in grams = no of moles x molecular mass. So, mass in grams = 5.2x 56 = 291.2g
