The amount of grams in two moles depends on the element or compound that you have two moles of. For example, the molar mass of oxygen is about 16 grams. So two moles of oxygen would be about 32 grams.
For this you need the atomic (molecular) mass of CH2O. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel. CH2O=30.0 grams
2.000 moles CH2O × (30.0 grams) = 60.0 grams CH2O
The atomic weight of H is 1.00794 g/mole. Therefore, the molecular weight of H2 is 2 x 1.00794g/mole = 2.01588g/mole. And two moles of H2 would be 2 x 2.01588g/mole = 4.03176g
2 moles of methane is equivalent to 32,08 g.
2 moles of water equal 64 g.
2 moles of iron is equal to 111,69 g.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
987 grams of Ra(OH)2 is equivalent to 3,78 moles.
124,60 grams of Fe3(PO4)2 are equal to 0,35 moles.
987 grams of Ra(OH)2 is equal to 3,78 moles.
The answer is 2 moles.
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
1) First find the number of moles of methane in 27.8 g using the molar mass.See the Related Question to the left of this answer "How do you convert from grams to moles and also from moles to grams?" to do that.2) Then write the balanced reaction. Methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). See the related question "How do you balance a chemical reaction?" to do that.3) That will tell you the ratio of moles of methane to moles of oxygen (it will be 2 to 1). So from Part 1, multiply the number of moles of methane by 2 to get moles of oxygen. Then, use the Ideal Gas Law to find out how many liters that will take up at STP. Use the Related Question link "How do you solve Ideal Gas Law problems?" to do that.
987 grams of Ra(OH)2 is equivalent to 3,78 moles.
124,60 grams of Fe3(PO4)2 are equal to 0,35 moles.
987 grams of Ra(OH)2 is equal to 3,78 moles.
2 g HCl are equivalent to 0,0548 moles.
How many moles are present in 92 grams of ethyl alcohol?
The answer is 2 moles.
The answer is 14 moles.
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
The complete combustion of methane proceeds according to the equation: CH4 + 2 O2 = CO2 + 2 H2O. Therefore, each mole of methane produces two moles of water and 4 moles of methane will produce eight moles of water.