The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.
Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl2
1.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
First realize that it takes 3 CL2 to produce one mole of CHCl3. So take
1.50 moles of CHCl3 * 3 moles of Cl2 / 1 mole of CHCL3= 4.5 mole of Cl2
The the atomic weight of Cl2 is 35.5*2=71g.
4.5 mole of Cl2*71g= 319.5g. of Cl2 needed.
The molar mass (mass of 1 mole) of MgCl2 is 95.205 g/mol. To determine the mass of 1.5 mol MgCl2, multiply the moles by the molar mass.
Molar mass MgCl2 = (1 x 24.305 g/mol Mg) + (2 x 35.45 g/mol Cl) =95.205 g/mol MgCl2
1.5 mol MgCl2 x (95.205 g MgCl2)/(1 mol MgCl2) = 150 g MgCl2 (rounded to two significant figures)
The formula given shows that there are two atoms in each molecule. Therefore, the answer is 2 X 1.5 X Avogadro's Number = about 1.8 X 1024.
1.75 mole CHCl3 (6.02 X 10^23 mole CHCl3)
= 1.05 X 1024 atoms of CHCl3
====================
The number is 9,033.10e23 molecules.
The reaction is:
H2 + Cl2 = 2 HCl
The answer is 0,21 mol hydrogen.
Mg = 24.3Cl = 35.5 x 2 = 71
Total = 71 + 24.3 = 95.3 g = 1 moles MgCl2
1.5 moles x 95.3 g/mole = 143 grams
The mass of 1,5 moles of anhydrous MgCl2 is 142,82 g.
54 grams
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6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
Formula mass of MgCl2 = 24.3+2(35.5) = 95.3Amount of MgCl2 = 444/95.3 = 4.66mol4.66 moles of MgCl2 are contained within a 444g pure sample.
Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21 g/mol 124g of Mgcl2 contains moles= 95.21* 124=11806.04moles
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
The mass of 15 moles of tungsten is 2.757,6 g.
Molarity = moles of solute/Liters of solution ( 20.0 ml = 0.02 Liters ) moles of solute = Liters of solution * Molarity 0.02 Liters * 0.800 M MgCl2 = 0.016 moles MgCl2 -------------------------------
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
1 mole of MgCl2=95.21 grams (found on the periodic table) 17.5 g of MgCl2(1mole of MgCl2/95.21g of MgCl2)=.184 moles of MgCl2(grams cancel out and rounded to 3 sig. figs) .184 moles of MgCl2 (1 Liter/2.5 moles of MgCl2)=0.735L of MgCl2 (moles cancel and rounded to 3 sig figs) 0.735 L of MgCl2(1000 milliLiters/1 Liter)=73.5 mL of MgCl2 and round the answer to 2 sig figs which equals 74 milliLitersof MgCl2
Need moles MgCl2 75.0 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.7877 mole MgCl2 ================now, Molarity = moles of solute/Liters of solution ( 500.0 milliliters = 0.5 Liters ) Molarity = 0.7877 moles MgCl2/0.5 Liters = 1.58 M MgCl2 solution --------------------------------
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
Magnesium chloride, MgCl2, has a molecular mass of has a molar mass of 95.21 g/mol. So, 53.8 g MgCl / 95.21 g/mol is 0.565 mol MgCl2.