0.004kg to 4 grams.
-log(1.0 X 10^-4 M KOH) = 4 14 - 4 = 10 pH KOH ----------------
4 mol KOH/1 x 2 mol KCI/2 mol KOH x 74.55 g KCI/1 mol KCI Apex.
4mol KOH x 1 mol Mg(OH)2 x 58.31g Mg(OH) 1 2 mol KOH 1 mol Mg (OH)2
2 hydrogen atoms
If the KOH is in a moderately concentrated aqueous solution, the net reaction can be: 2 Al + 6 H2O => 2 Al(OH)3 + 3 H2. In this instance, the KOH does not undergo any net reaction; instead it catalyzes the reaction between aluminum and water by preventing the solid aluminum from maintaining a passivation layer on its surface. If the KOH is in a still more concentrated aqueous solution, the reaction can be: 2 Al + 4 KOH => K2Al2O4 + H2.
Balanced equation first.2H2 + O2 --> 2H2OGet moles products.4 grams H2 (1 mole H2/2.016 grams) = 1.984 moles H264 grams O2 (1 mole O2/32 grams) = 2.000 moles O2I suspect hydrogen gas of limiting and driving the reaction.1.984 moles H2 (1 mole O2/2 moles H2) = 0.992 moles O2 ( you have more than this in equation )2.000 moles O2 (2 mole H2/1 mole O2) = 4.000 moles H2 ( you do not have this much and H2 will drive this reaction )1.984 moles H2 (2 moles H2O/2 moles H2)(18.016 grams/1 mole H2O)= 36 grams water produced====================
4mol KOH/1x2mol KCl/2mol KOHx74.55 gKCl/1 mol KCl
Jenny Koh is 5' 4".
0.004kg to 4 grams.
Jenny Koh is 5' 4".
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
-log(1.0 X 10^-4 M KOH) = 4 14 - 4 = 10 pH KOH ----------------
4
About 1,814 grams. There are 453.59 grams in one pound, so there are 4 times that many in 4 pounds.
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