It depends how strong a solution you want to make.
The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre.
For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.
4% NaCl (w/v) = 4 grams/100 mls = 40 grams/liter
The answer is 40 g NaCl.
The answer is 1 g.
If your solution is a total of 414g and 3.06% of it needs to be NaCl, then you just take 414 x .0306 = grams of NaCl. The rest of the grams will be from other species in the solution.
The answer is 8 g NaCl.
Gram percent is the number of grams of a solute per 100 grams of a solution. For example, if a solution of NaCl and water was said to have a 0.02g% of NaCl, this would mean that for 100g of saline solution, 0.02 of those grams are salt. Since 1L of water weighs 1kg (at normal conditions), there would be .2g of NaCl in 1L of a 0.02g% NaCl solution.
20mg
A 0.0% NaCl solution is a solution with absolutely no NaCl.
600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl
50 g
No, not exactly.Mass mass percent concentration measures grams of solute per 100 grams of solution (= solvent + solute)Example:58.5 g NaCl (solute) added to941.5 g H2O (solvent) gives you1000.0 g solution of 5.85% NaCl (= 100%*58.5/1000.0),which is about a 1.0 mol/L NaCl solution.
Molarity = moles of solute/volume of solution. 1 liter = 1000 millilitetrs 3.00M = X Moles/1000ml = 3000 millimoles, or 3 moles NaCl 3 moles NaCl (58.44g NaCl/1mol NaCl ) = 175.32 grams needed. About 4/10 of a pound of salt.
The mass of sodium hypochlorite in 2,5 kg solution is 131,25 g.Sodium chloride is only the product of a decomposition.
The answer is 28,81 %.
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.