The gram Atomic Mass of calcium is 40.08, the formula of anhydrous calcium chloride is CaCl2, showing that each formula unit contains one calcium atom, and the gram formula mass of anhydrous calcium chloride is 110.99. Therefore, 19050.9 grams of calcium chloride contains 19050.9(40.08/110.99) or 6.880 X 103 grams, to the justified* number of significant digits.
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*There may well be tables of gram atomic and gram formula masses more modern than the one I am using that would allow for more significant digits in the answer.
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
120
120 grams of calcium contain 2,994 moles.
Lithium chloride is not transformed in calcium chloride.
science
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
3.5 X 10^24
1.47g
Answering "http://wiki.answers.com/Q/How_many_grams_of_calcium_chloride_are_needed_to_produce_10_g_of_potassium_chloride"
The chemical formula for calcium chloride is CaCl2, and its formula weight is 110.99. The formula shows that each formula weight of calcium chloride contains one mole of calcium ions. In 166.5 grams, there are 166.5/110.99 or 1.500 formula weights of calcium chloride and the same number of moles of calcium ions.
The answer is 18,26 g CaCl2.
Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.
The formula unit for calcium chloride is CaCl2. There are two chloride ions in one formula unit of calcium chloride. We can also say that there are two moles chloride ions in one mole of CaCl2.
Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams