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319g Cl2 are needed.
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
To completely react with 0.65 g of H2 to produce HCl we need 23.08 g chlorine.
201
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
319g Cl2 are needed.
70
6
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
To completely react with 0.65 g of H2 to produce HCl we need 23.08 g chlorine.
10.1 grams
When sulfur reacts with chlorine to produce disulfur dichloride, the name of the compound corresponds to a chemical formula of S2Cl2, which shows that the same numbers of atoms of each element are needed to form the compound. The gram atomic mass of sulfur is 32.06, and the gram atomic mass of chlorine is 35.453. 200.2 grams of sulfur corresponds to 200.2/32.06 or about 6.2445 gram atoms of sulfur, while 100.3 grams of chlorine corresponds to 100.3/35.453 or about 2.83 gram atoms of chlorine. Therefore, chlorine is the limiting reactant among these amounts of sulfur and chlorine.
16,45 g nitrogen are needed.
A lot
This question can not be answered, not even by your teacher: not enough correct information." How many grams (of WHAT ?) would 29.48 L of chlorine gas produce (after doing WHAT ?) "
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.
Si + 2Cl2 --> SiCl4 24.4 grams silicon (1 mole Si/28.09 grams)(2 mole Cl2/1 mole Si)(70.9 grams/1 mole Cl2) = 123 grams chlorine needed =====================