Assume it is a copper 2 salt and no side reactions it would require 96485 x 2 coulombs of charge per mole of copper or per 63.5 g of copper.
1 coulomb is 1 amp.second
so 7.5 x 600 x 3600 x 63.5 / (96485 x 2) g = 5331 g Cu
Cathode
During the electrolysis of Copper sulphate ,at the cathode ,copper and hydrogen both being positively charged migrate towards the cathode.While at the anode
The color fades as there is a discharge of copper two ions to form copper atoms
No
Chlorine Gas is evolved at the anode.
Cathode
Because the cathode is where reduction takes place, meaning the it gains electrons. When it gains electrons, it attracts the copper cation (Cu^2+) and as the copper cation reaches the cathode, it picks up the electrons from the cathode, and is deposited as solid copper (Cu). This results in the cathode gaining mass over time.
During the electrolysis of Copper sulphate ,at the cathode ,copper and hydrogen both being positively charged migrate towards the cathode.While at the anode
Copper can be refined by electrorefinning.
The color fades as there is a discharge of copper two ions to form copper atoms
electrode
The cathode, where the +ions in solution accept electrons and become neutral metal atoms.
You do not mention what you are using as the anode and cathode, but i would assume that given the green colour you are using copper or brass perhaps as the anode, and it is breaking down into a copper carbonate(which is green). By applying electrical current to the circuit you are speeding up the conversion of copper to copper carbonate(or similar).
During this electrolysis are obtained chlorine and sodium.
the cathode and anode keeps interchanging between each other
conclusion of electric current
Usually in a school experiment, you put copper solution into glass. Then you add Positively and negatively charged sticks which are connected with each other and plugged into electricity, which makes pure copper form on the negatively charged stick.