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Assume it is a copper 2 salt and no side reactions it would require 96485 x 2 coulombs of charge per mole of copper or per 63.5 g of copper.

1 coulomb is 1 amp.second

so 7.5 x 600 x 3600 x 63.5 / (96485 x 2) g = 5331 g Cu

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Q: How many grams of copper would be deposited during electrolysis of copper salt by a current of 7.50A for 600 hours?
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