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What is the molar concentration of a 0.9 percent glucose solution?
Wiki User
∙ 11y ago
1% (presumably m/v) glucose solution would contain 1 g of glucose per 100 ml of solution. Therefore the conversion of 1 g / 100 ml to units of mol/L requires that we divide by the molar mass and multiply by the conversion factor of ml to L. Therefore: (1 g / 100 ml) * (1 mol / 180.16 g) * (1000 ml / 1 L) = 0.0555 M = 0.06 M.
Wiki User
∙ 14y ago
Wiki User
∙ 11y ago5.00% mass/volume glucose = 5.00 g glucose / 100 mL solution
5.00 g C6H12O6 x (1 mole C6H12O6 / 180.2 g C6H12O6) = 0.0277 moles glucose
M glucose = moles / L = (0.0277 / 0.100) = 0.277 M
Wiki User
∙ 14y ago1M, which is also 18% ==
cheers to all idiots online!
Wiki User
∙ 13y ago9 grams of glucose to get a 0.9% glucose (g) to water (ml)
Wiki User
∙ 11y ago1.5 x 10-4 moldm-3
Wiki User
∙ 11y agoThe answer is 18,016 %.
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