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How much do you determine the molarity of a solution of 10 grams of NaOH in 500 mL of solution?
To convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.
To convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.
molar mass of NaOH = 23 + 16 + 1 = 40 g/mole
10.0 g x 1 mol/40 g /0.500 L = 0.500 M
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How is a concentrated solution prepared?
3 Simple Steps!NOTE: Use this answer to make a solution if you need to dissolve a SOLID to make your solution. If instead you are making a solution by diluting another solution, see the Related Questions link for "How do you prepare a solution by diluting another solution?" You must know two things to make a solution: the number of moles of the solute, and the number of liters of solution. That is how the concentration "molarity" (M) is defined: the moles per liter:-- Molarity = moles of solute ÷ liters of solutionor-- Moles of solute = Molarity * liters of solutionNote: The volume is liters of solution, not solvent. That means that the total volume of the solution is what matters, not how much liquid you add.So, to make a solution of a specific concentration, we must figure out how many moles of solute we need. That's easy! Let me illustrate with a few simple examples. Then we'll find how many grams that corresponds to.--- Example 1: How many moles of lithium chloride (LiCl) are needed to make 1 liter of 0.5 M LiCl solution?--- Answer: In 1 liter of 0.5 M LiCl, there are 0.5 moles of LiCl. Therefore the answer is 0.5 moles LiCl.--- Example 2: How many more of sodium hydroxide (NaOH) are needed to make 2 liters of 0.5 M NaOH?--- Answer: In 1 liter of 0.5 M NaOH, there are 0.5 moles. So in 2 liters, there will be 1.0 moles. So the answer is 1.0 moles NaOH.--- Example 3: How many moles of silver nitrate (AgNO3) are needed to make 3.7 liters of 0.43 M AgNO3 solution?--- Answer: Same as before, but the math is more complicated. In 1 liter, there are 0.43 moles, so in 3.7 liters, there are 0.43 * 3.7 = 1.591 moles.Now we can't measure moles directly, so we need to find the number of grams of the solute so we can weigh it out. Once we've found the number of moles, we can convert that to grams from the molar mass of the substance (or atomic mass of the element). We need the periodic table for this (see the link below for a periodic table). Again, let me illustrate with a couple of examples. In fact I'll use the same examples as before.--- Example 1: How many grams of LiCl are needed to make 1 liter of 0.5 M LiCl?--- Answer: From before we figured out that we need 0.5 moles of LiCl. So how many grams is that? We first need to calculate the molar mass of LiCl. From the periodic table, the atomic weight of lithium (Li) is 6.941 grams per mole and the weight of chlorine (Cl) is 35.453 grams per mole. So the atomic mass of LiCl is: 6.941 + 35.453 = 42.394 grams per mole. So if we need 0.5 moles, than to find the grams, we just multiply: 0.5 moles * 42.394 grams/mole = 21.197 grams So, to make 1 liter of 0.5 M LiCl, we need to add 21.197 grams of HCl and add enough water to make the total volume equal 1 liter.--- Example 2: How many NaOH are need to make 2 liters of 0.5 M NaOH?--- Answer: From before, we know we need 1 mole of NaOH. The molar mass of NaOH is equal to: 22.9898 + 15.999 + 1.0079 = 39.9967 grams per mole So since we need 1 mole, we add 39.9967 grams of NaOH and add water until we have a total of 2 liters of solution.--- Example 3: How many grams of AgNO3 are needed to make 3.7 liters of 0.43 M acetic acid solution?--- Answer: Again, from before we know we need 1.591 moles of AgNO3. To find the number of grams, we must find the molar mass. So the molar mass of AgNO3 is: 107.868 + 14.007 + (3*15.999) = 169.873 g/mole So to find the number of grams, we just multiply: 1.591 moles * 169.873 g/mole = 270.268 grams. So we must add 270.268 grams of acetic acid, and then add enough water to make the total volume 3.7 liters. (Of course, that'd be really very expensive because silver nitrate is not cheap, and that a lot of it!)TO SUMMARIZE HOW TO MAKE A SOLUTION:1) From the concentration and the volume given to you in the problem, first find the number of moles of solute:Moles of solute = Concentration * Volume (or moles = molarity * liters)2) Then convert moles to grams using the molar mass:Number of grams = Number of moles * Molar mass (or grams = moles grams per mole)3) Then add water to the solid until the TOTAL volume of the solution is the correct amount you need.
If the concentration of one material in a solution is given what additional information will be needed to find the concentration of a second material in the solution?
You need the volume of the solution and the stoiciometric coefficients. You must first find the moles of the first substance, by multiplying the molarity (M) by the volume (L). Once you have moles, you can compare the two substances by looking at the coefficients in your chemical equation. For instance, if your chemical equation is: HCl + NaOH --> H2O + NaCl you have a 1:1 ratio. Therefore the moles of HCl = the moles of NaOH however if you have 2H2O --> 2H2 + O2 the ratio of H2O to O2 is 2:1; the moles of H2O = 2 x the moles of O2
Why was the conical flask not washed with the alkali solution it was going to contain during titration?
So that no extra moles of NaOH were present in the flask.
Mixing acetone and sodium hydroxide?
oxidation-reductionWhat type of a reaction occurs when a sodium hydroxide solution is mixed with an acetic acid solution?The answer above is wrong. The correct answer is acid-base neutralization
Does Buret measure volume and mass?
Well i suggest you just restart science again if your asking questions like that. A burette measure volume, and well there isn't any point you'd want it to measure mass, if you're putting 25cm^3 of NaOH in it for example at 1mol dm^-3 means for every 1 litre (1000cm's^3 or 1dm)theres 40 grams of NaOH (a mole of NaOH weighs 40 grams or 4.0x10^-3kg's), but you only have 25cm^3 so that's like 40 times less to begin with so theres only 1 gram of NaOH in th 25cm^3 so it would weigh 26 grams. Water which is what the NaOH would be dissolved in is very good for mass, 1cm cubed weighs 1 gram or if your American whatever backwards unit you use for weight as water has a density of of very close to 1.
How many grams of NaOH are in 350 mL of a 2.5 M of NaOH solution?
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
To calculate the molarity, you first need to convert the grams of NaOH to moles using the molar mass of NaOH (40 g/mol). Then, you divide the moles of NaOH by the volume of solution in liters (450 ml = 0.45 L) to get the molarity. Molarity = moles of NaOH / volume of solution in liters Moles of NaOH = 95 g / 40 g/mol = 2.375 mol Molarity = 2.375 mol / 0.45 L = 5.28 M
What is the molarity of 32.0 of NaOH in 450 of NaOH solution?
To find the molarity, you first need to calculate the number of moles of NaOH using the formula: moles = mass / molar mass. Given that the molar mass of NaOH is 40 g/mol, you can calculate the moles of NaOH in 32.0 g. Next, divide the moles by the volume of the solution in liters (450 mL = 0.450 L) to find the molarity.
What is the molarity of a solution made by dissolving 2 moles of Na OH in 6 kg of water?
The molarity of a solution is typically expressed in moles of solute per liter of solution. To determine the molarity in this case, we would need to convert the mass of water to volume (1 kg of water ≈ 1 L), and then calculate the molarity using the number of moles of NaOH and the total volume of the solution.
What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?
To find the concentration of OH- in the solution, first calculate the number of moles of NaOH using its molar mass. Then, divide the moles of NaOH by the volume of the solution to find the molarity of NaOH. Since NaOH dissociates into one Na+ and one OH-, the molarity of OH- will be the same as the molarity of NaOH.
How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
To prepare a 0.4M NaOH solution in 500mL, you would need 20g of solid NaOH. This is calculated by multiplying the molarity by the volume in L and the molar mass of NaOH. (0.4 mol/L) * (0.5 L) * (40 g/mol) = 20g.
How many grams of NaOH(MW40.0) are there in 400.0 ml of a 0.175 M NaOH solution?
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
How much NaOH is in 4.7L of a 0.57 M NaOH solution?
To calculate the amount of NaOH in the solution, multiply the volume (4.7 L) by the molarity (0.57 mol/L). Amount of NaOH = Volume (L) x Molarity (mol/L) = 4.7 L x 0.57 mol/L = 2.679 moles of NaOH.
What is the molarity of 15 g NaOH in a 100 L aqueous solution?
To determine the molarity of 15 g NaOH in a 100 L solution, first calculate the moles of NaOH using its molar mass (40 g/mol). Then, divide the moles by the volume in liters (100 L) to get the molarity. The molarity of the NaOH solution would be 0.375 M.
What is the molArity of a hydrochloric acid solution 30.0mL of which is just neutralized by 48.0mL of 0.100M NaOH?
The reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is 1:1, so the moles of NaOH used in the reaction can be used to determine the moles of HCl in the solution. Using the volume and concentration of NaOH, you can calculate the moles of NaOH used. Then, using the balanced equation, you can determine the moles of HCl, which can be used to find the molarity of HCl in the solution.
How many grams of NaOH would you need to make 4 litters of 8 M NaOH?
To calculate the grams of NaOH needed, use the formula: grams = molarity x volume x molar mass. First, convert the volume to liters (4 liters). Next, calculate the grams using 8 M as the molarity and the molar mass of NaOH. This will give you the amount of NaOH required to make 4 liters of 8 M NaOH solution.
How many grams of NaOH are in 350 mL of a 5.7 M NaOH solution?
To calculate the grams of NaOH in the solution, first convert the volume from milliliters to liters by dividing by 1000. Then use the formula: moles = molarity x volume. Finally, multiply the moles of NaOH by its molar mass (40 g/mol) to find the grams. In this case, it would be: (5.7 mol/L) x (0.35 L) x (40 g/mol) = 79.8 grams of NaOH.
