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How much do you determine the molarity of a solution of 10 grams of NaOH in 500 mL of solution?
Leehakisanjuan
To convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.
Alexandro Russel
Wiki User
∙ 10y agoTo convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.
Wiki User
∙ 13y ago80.0 g in 500 ml = 160.0 g in 1000 ml so 160/40 = 4.0 Molar
Wiki User
∙ 7y agomolar mass of NaOH = 23 + 16 + 1 = 40 g/mole
10.0 g x 1 mol/40 g /0.500 L = 0.500 M
Wiki User
∙ 7y agoThe concentration is 20 g/L or 0,5 molar.
Wiki User
∙ 13y agoThe solution is 4 Molar.
Wiki User
∙ 9y agoThis molarity is 0,5.
Wiki User
∙ 10y ago1.5 M
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How is a concentrated solution prepared?
3 Simple Steps!NOTE: Use this answer to make a solution if you need to dissolve a SOLID to make your solution. If instead you are making a solution by diluting another solution, see the Related Questions link for "How do you prepare a solution by diluting another solution?" You must know two things to make a solution: the number of moles of the solute, and the number of liters of solution. That is how the concentration "molarity" (M) is defined: the moles per liter:-- Molarity = moles of solute ÷ liters of solutionor-- Moles of solute = Molarity * liters of solutionNote: The volume is liters of solution, not solvent. That means that the total volume of the solution is what matters, not how much liquid you add.So, to make a solution of a specific concentration, we must figure out how many moles of solute we need. That's easy! Let me illustrate with a few simple examples. Then we'll find how many grams that corresponds to.--- Example 1: How many moles of lithium chloride (LiCl) are needed to make 1 liter of 0.5 M LiCl solution?--- Answer: In 1 liter of 0.5 M LiCl, there are 0.5 moles of LiCl. Therefore the answer is 0.5 moles LiCl.--- Example 2: How many more of sodium hydroxide (NaOH) are needed to make 2 liters of 0.5 M NaOH?--- Answer: In 1 liter of 0.5 M NaOH, there are 0.5 moles. So in 2 liters, there will be 1.0 moles. So the answer is 1.0 moles NaOH.--- Example 3: How many moles of silver nitrate (AgNO3) are needed to make 3.7 liters of 0.43 M AgNO3 solution?--- Answer: Same as before, but the math is more complicated. In 1 liter, there are 0.43 moles, so in 3.7 liters, there are 0.43 * 3.7 = 1.591 moles.Now we can't measure moles directly, so we need to find the number of grams of the solute so we can weigh it out. Once we've found the number of moles, we can convert that to grams from the molar mass of the substance (or atomic mass of the element). We need the periodic table for this (see the link below for a periodic table). Again, let me illustrate with a couple of examples. In fact I'll use the same examples as before.--- Example 1: How many grams of LiCl are needed to make 1 liter of 0.5 M LiCl?--- Answer: From before we figured out that we need 0.5 moles of LiCl. So how many grams is that? We first need to calculate the molar mass of LiCl. From the periodic table, the atomic weight of lithium (Li) is 6.941 grams per mole and the weight of chlorine (Cl) is 35.453 grams per mole. So the atomic mass of LiCl is: 6.941 + 35.453 = 42.394 grams per mole. So if we need 0.5 moles, than to find the grams, we just multiply: 0.5 moles * 42.394 grams/mole = 21.197 grams So, to make 1 liter of 0.5 M LiCl, we need to add 21.197 grams of HCl and add enough water to make the total volume equal 1 liter.--- Example 2: How many NaOH are need to make 2 liters of 0.5 M NaOH?--- Answer: From before, we know we need 1 mole of NaOH. The molar mass of NaOH is equal to: 22.9898 + 15.999 + 1.0079 = 39.9967 grams per mole So since we need 1 mole, we add 39.9967 grams of NaOH and add water until we have a total of 2 liters of solution.--- Example 3: How many grams of AgNO3 are needed to make 3.7 liters of 0.43 M acetic acid solution?--- Answer: Again, from before we know we need 1.591 moles of AgNO3. To find the number of grams, we must find the molar mass. So the molar mass of AgNO3 is: 107.868 + 14.007 + (3*15.999) = 169.873 g/mole So to find the number of grams, we just multiply: 1.591 moles * 169.873 g/mole = 270.268 grams. So we must add 270.268 grams of acetic acid, and then add enough water to make the total volume 3.7 liters. (Of course, that'd be really very expensive because silver nitrate is not cheap, and that a lot of it!)TO SUMMARIZE HOW TO MAKE A SOLUTION:1) From the concentration and the volume given to you in the problem, first find the number of moles of solute:Moles of solute = Concentration * Volume (or moles = molarity * liters)2) Then convert moles to grams using the molar mass:Number of grams = Number of moles * Molar mass (or grams = moles grams per mole)3) Then add water to the solid until the TOTAL volume of the solution is the correct amount you need.
If the concentration of one material in a solution is given what additional information will be needed to find the concentration of a second material in the solution?
You need the volume of the solution and the stoiciometric coefficients. You must first find the moles of the first substance, by multiplying the molarity (M) by the volume (L). Once you have moles, you can compare the two substances by looking at the coefficients in your chemical equation. For instance, if your chemical equation is: HCl + NaOH --> H2O + NaCl you have a 1:1 ratio. Therefore the moles of HCl = the moles of NaOH however if you have 2H2O --> 2H2 + O2 the ratio of H2O to O2 is 2:1; the moles of H2O = 2 x the moles of O2
Why was the conical flask not washed with the alkali solution it was going to contain during titration?
So that no extra moles of NaOH were present in the flask.
Mixing acetone and sodium hydroxide?
oxidation-reductionWhat type of a reaction occurs when a sodium hydroxide solution is mixed with an acetic acid solution?The answer above is wrong. The correct answer is acid-base neutralization
Does Buret measure volume and mass?
Well i suggest you just restart science again if your asking questions like that. A burette measure volume, and well there isn't any point you'd want it to measure mass, if you're putting 25cm^3 of NaOH in it for example at 1mol dm^-3 means for every 1 litre (1000cm's^3 or 1dm)theres 40 grams of NaOH (a mole of NaOH weighs 40 grams or 4.0x10^-3kg's), but you only have 25cm^3 so that's like 40 times less to begin with so theres only 1 gram of NaOH in th 25cm^3 so it would weigh 26 grams. Water which is what the NaOH would be dissolved in is very good for mass, 1cm cubed weighs 1 gram or if your American whatever backwards unit you use for weight as water has a density of of very close to 1.
What is the molarity of 32.0 of NaOH in 450 of NaOH solution?
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
A solution of NaOH contains 20g of this compound in 2dm3 of this solution . What is molarity of this solution?
This sodium hydroxide solution has a molarity of 0,25.
How many grams of solid NaOH are needed to prepare 500mL NaOH solution with a concentration of 0.4M?
molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M
What is the molarity of a solution of 95 grams of NaOH to 450 ml of water?
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
How much NaOH is in 4.7L of a 0.57 M NaOH solution?
Molarity = moles of solute/volume of solution so, 29.4 grams sounds about right.
How many grams of NaOH are in 350 mL of a 5.7 M NaOH solution?
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
How much NaOH is in 3.8 L of a 0.53 M NaOH solution?
Molarity = moles of solute/volume of solution 0.53 M NaOH = moles NaOH/3.8 Liters = 2.014 moles, or about 80 grams
What is the molarity of a solution with 2 moles of NaOH in 1620ml of water?
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
What mass of NaOH is in 290 mL of a 1.7 M NaOH solution?
197.2 grams of NaOH is present in 290ml of 1.7 NaoH solution as the formula for Molarity is Mass of solute x 1000/ equivalent mass x volume
What is the molarity of a solution made by dissolving 2 moles of Na OH in 6 kg of water?
6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------
What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
What is the molarity of a solution that contains 10.0g of NaOH in 400.0 ml of NaOH of solution?
The answer is 0,625 moles.
