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To convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.

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To convert to per litre we multiply weight by 2. This gives 40 grams per litre. 40g divided by 40g/mol is a 1 molar solution.

80.0 g in 500 ml = 160.0 g in 1000 ml so 160/40 = 4.0 Molar

molar mass of NaOH = 23 + 16 + 1 = 40 g/mole

10.0 g x 1 mol/40 g /0.500 L = 0.500 M

The concentration is 20 g/L or 0,5 molar.

The solution is 4 Molar.

This molarity is 0,5.

1.5 M

Q: How much do you determine the molarity of a solution of 10 grams of NaOH in 500 mL of solution?

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3 Simple Steps!NOTE: Use this answer to make a solution if you need to dissolve a SOLID to make your solution. If instead you are making a solution by diluting another solution, see the Related Questions link for "How do you prepare a solution by diluting another solution?" You must know two things to make a solution: the number of moles of the solute, and the number of liters of solution. That is how the concentration "molarity" (M) is defined: the moles per liter:-- Molarity = moles of solute Ã· liters of solutionor-- Moles of solute = Molarity * liters of solutionNote: The volume is liters of solution, not solvent. That means that the total volume of the solution is what matters, not how much liquid you add.So, to make a solution of a specific concentration, we must figure out how many moles of solute we need. That's easy! Let me illustrate with a few simple examples. Then we'll find how many grams that corresponds to.--- Example 1: How many moles of lithium chloride (LiCl) are needed to make 1 liter of 0.5 M LiCl solution?--- Answer: In 1 liter of 0.5 M LiCl, there are 0.5 moles of LiCl. Therefore the answer is 0.5 moles LiCl.--- Example 2: How many more of sodium hydroxide (NaOH) are needed to make 2 liters of 0.5 M NaOH?--- Answer: In 1 liter of 0.5 M NaOH, there are 0.5 moles. So in 2 liters, there will be 1.0 moles. So the answer is 1.0 moles NaOH.--- Example 3: How many moles of silver nitrate (AgNO3) are needed to make 3.7 liters of 0.43 M AgNO3 solution?--- Answer: Same as before, but the math is more complicated. In 1 liter, there are 0.43 moles, so in 3.7 liters, there are 0.43 * 3.7 = 1.591 moles.Now we can't measure moles directly, so we need to find the number of grams of the solute so we can weigh it out. Once we've found the number of moles, we can convert that to grams from the molar mass of the substance (or atomic mass of the element). We need the periodic table for this (see the link below for a periodic table). Again, let me illustrate with a couple of examples. In fact I'll use the same examples as before.--- Example 1: How many grams of LiCl are needed to make 1 liter of 0.5 M LiCl?--- Answer: From before we figured out that we need 0.5 moles of LiCl. So how many grams is that? We first need to calculate the molar mass of LiCl. From the periodic table, the atomic weight of lithium (Li) is 6.941 grams per mole and the weight of chlorine (Cl) is 35.453 grams per mole. So the atomic mass of LiCl is: 6.941 + 35.453 = 42.394 grams per mole. So if we need 0.5 moles, than to find the grams, we just multiply: 0.5 moles * 42.394 grams/mole = 21.197 grams So, to make 1 liter of 0.5 M LiCl, we need to add 21.197 grams of HCl and add enough water to make the total volume equal 1 liter.--- Example 2: How many NaOH are need to make 2 liters of 0.5 M NaOH?--- Answer: From before, we know we need 1 mole of NaOH. The molar mass of NaOH is equal to: 22.9898 + 15.999 + 1.0079 = 39.9967 grams per mole So since we need 1 mole, we add 39.9967 grams of NaOH and add water until we have a total of 2 liters of solution.--- Example 3: How many grams of AgNO3 are needed to make 3.7 liters of 0.43 M acetic acid solution?--- Answer: Again, from before we know we need 1.591 moles of AgNO3. To find the number of grams, we must find the molar mass. So the molar mass of AgNO3 is: 107.868 + 14.007 + (3*15.999) = 169.873 g/mole So to find the number of grams, we just multiply: 1.591 moles * 169.873 g/mole = 270.268 grams. So we must add 270.268 grams of acetic acid, and then add enough water to make the total volume 3.7 liters. (Of course, that'd be really very expensive because silver nitrate is not cheap, and that a lot of it!)TO SUMMARIZE HOW TO MAKE A SOLUTION:1) From the concentration and the volume given to you in the problem, first find the number of moles of solute:Moles of solute = Concentration * Volume (or moles = molarity * liters)2) Then convert moles to grams using the molar mass:Number of grams = Number of moles * Molar mass (or grams = moles grams per mole)3) Then add water to the solid until the TOTAL volume of the solution is the correct amount you need.

You need the volume of the solution and the stoiciometric coefficients. You must first find the moles of the first substance, by multiplying the molarity (M) by the volume (L). Once you have moles, you can compare the two substances by looking at the coefficients in your chemical equation. For instance, if your chemical equation is: HCl + NaOH --> H2O + NaCl you have a 1:1 ratio. Therefore the moles of HCl = the moles of NaOH however if you have 2H2O --> 2H2 + O2 the ratio of H2O to O2 is 2:1; the moles of H2O = 2 x the moles of O2

So that no extra moles of NaOH were present in the flask.

oxidation-reductionWhat type of a reaction occurs when a sodium hydroxide solution is mixed with an acetic acid solution?The answer above is wrong. The correct answer is acid-base neutralization

Well i suggest you just restart science again if your asking questions like that. A burette measure volume, and well there isn't any point you'd want it to measure mass, if you're putting 25cm^3 of NaOH in it for example at 1mol dm^-3 means for every 1 litre (1000cm's^3 or 1dm)theres 40 grams of NaOH (a mole of NaOH weighs 40 grams or 4.0x10^-3kg's), but you only have 25cm^3 so that's like 40 times less to begin with so theres only 1 gram of NaOH in th 25cm^3 so it would weigh 26 grams. Water which is what the NaOH would be dissolved in is very good for mass, 1cm cubed weighs 1 gram or if your American whatever backwards unit you use for weight as water has a density of of very close to 1.

Related questions

I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH

This sodium hydroxide solution has a molarity of 0,25.

molarity equals moles of solute /volume of solution in litres . moles of NaOH equals 5g/40g = 0.125 and volume of solution will be volume of water + volume of NaOH = 0.5 litre+0.002 l which is nearly 0.5 litre . (volume of NaOH is calculated by its density) so molarity = 0.125mol/0.5litre = 0.25 M

95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28

Molarity = moles of solute/volume of solution so, 29.4 grams sounds about right.

Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------

Molarity = moles of solute/volume of solution 0.53 M NaOH = moles NaOH/3.8 Liters = 2.014 moles, or about 80 grams

1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============

197.2 grams of NaOH is present in 290ml of 1.7 NaoH solution as the formula for Molarity is Mass of solute x 1000/ equivalent mass x volume

6 kg = 6000 grams and density of water = 1.00 grams/milliliters. 1.00 g/ml = 6000 grams/X ml = 6000 ml which = 6 liters ======================== Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/6 Liters = 0.3 M NaOH solution -----------------------------

Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------

The answer is 0,625 moles.