30.8g of iron (approximately) reacted with 13.2g of oxygen will yield 44g of iron(III) oxide (Fe2O3) with 2.8g of oxygen left unreacted. This assumes Atomic Mass numbers of 56 and 16 respectively for iron and oxygen. The actual mass number of iron is 55.847 and oxygen 15.9994 making the figures 30.775g of iron and 13.225g of oxygen with 2.775g of unreacted oxygen. Of course this is an exothermic reaction so will there be a tiny tiny loss of mass in the system as it is converted to heat energy, according to E=MC^2? I'll let you work that one out...
Iron(III) oxide is composed of one iron atom and three oxygen atoms. Therefore, if we have 44 grams of iron(III) oxide, we can calculate the mass of iron by subtracting the mass of oxygen. 44g - 16g (mass of oxygen) = 28g of iron is needed to combine with 16g of oxygen to form 44g of iron(III) oxide.
62 grams a+
62 grams a+
An oxygen atom can only be oxidized by some element with an equal or higher electronegativity. So, oxygen can be oxidized by fluorine (e.g., OF2) or by another oxygen atom (e.g., O2).
The chemical formula for Calcium Oxide is CaO. The Atomic weigth of Calcium is 40.078. The Atomic weight of Oxygen is 15.999 The Molecular weight of CaO is therefore 56.077 Thus 100g of CaO would contain (15.999/56.077)*100 = 28.53041353852738 grams of Oxygen and (40.078/56.077)*100 = 71.46958646147262 grams of Calcium.
aluminium nitrate
Sounds like 42.2 grams, but I haven't checked your proportions, are these stoichometric?
2
Sulphur + oxygen = Sulphur Oxide
To find the mass of oxygen needed to produce 13 grams of the oxide, we first find the molar ratio between P and O in the product. Then, use this ratio to calculate the mass of oxygen needed. Since 71g of the oxide contains 31g of phosphorus, we can calculate the mass of oxygen needed for 13g of the oxide by setting up a proportion.
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
62 grams a+
62 grams a+
The radium oxide is formed.
If 20g of mercury oxide were heated, the combined mass of oxygen and mercury would be 20 grams.
If 3 grams of magnesium are used to form 4 grams of magnesium oxide, then 1 gram of oxygen is used in the reaction. This means 1 gram of oxygen remains unused.
Iron oxide is formed by the reaction of iron and oxygen in a 1:1 ratio by mass. Therefore, the 55 g of iron will react completely with 55 g of oxygen to form iron oxide.
The molar mass of magnesium is 24.3 g/mol and oxygen is 16 g/mol. The balanced equation is 2Mg + O2 -> 2MgO. Since magnesium and oxygen react in a 1:1 ratio, all magnesium reacted to form magnesium oxide. Therefore, 2.5 grams of magnesium oxide was formed.