Want this question answered?
84.995g
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
Learn spelling first, then come back... KCl Degrees Celcius
Solubility of NaNO3 is 1.25 kg/kgwater. There are solubility vs temperature curve of many sodium salt available in the internet and text book.
100 g water dissolve 45,8 g potassium chloride at 50 o 0C.
67.0 grams of caffeine will dissolve in 100 mL of water at 100 degrees Celsius. 100mL of water = 100g of water so.. 67.0 grams of water will dissolve in 100 grams of water at 100 degrees Celsius. I pretty sure this is right, I was searching for the answer myself and it seems to work. But more accurately you will need to find the density of water at 100 ºC which is 0.9584 g/mL. So, 100g/0.9584 g/mL equals about 104 mL. Then 104 mL x 67.0g/100 mL = 69.9 g.
110 g.
The solubility of poassium nitrate in water at 20 oC is 616 g/L.
20
20
Instead of waiting for the answer, I ended up solving it. lol 300grams of H20 X 110grams of KNO3/100 grams of H20 = 330 grams of KNO3 The grams of H20 both cancel out and leave you with 330 grams of KNO3 Containing the solubility of KNO3. At 60 degrees celsius the KNO3 grams were 110, which is (over) / 100grams of H20. Hope this helps with this workbook problem :)
400