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No lone pairs on the N in the nitrate anion (NO3^-)
122 grams of anhydrous Cu(NO3)2 contain 3,92.10e23 molecules.
13.5g Mg(NO3)2 x 1 mol Mg(NO3)2/148.3 = 0.0910 mol Mg(NO3)2
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If you are referring to the nitrate ion, NO3-, the oxidation number of oxygen would be O2- and nitrogen would be N5+. If you are talking about nitrogen trioxide NO3, the oxidation number of oxygen would be O2- and nitrogen would be N6+. Edit: Nitrogen trioxide does not exist in its free state.
The species is; Ca(NO3)2 ( NO3(-) is a polyatomic ion and is in parenthesis ) 7.5 grams Ca(NO3)2 (1 mole Ca(NO3)2/164.1 grams)(2 mole N/1 mole Ca(NO3)2)(6.022 X 10^23/1 mole N) = 5.5 X 10^22 atoms of nitrogen
No lone pairs on the N in the nitrate anion (NO3^-)
3 nitrogen atoms.
122 grams of anhydrous Cu(NO3)2 contain 3,92.10e23 molecules.
In each molecule of NO3, there is one nitrogen atom and there are three oxygen atoms.
13.5g Mg(NO3)2 x 1 mol Mg(NO3)2/148.3 = 0.0910 mol Mg(NO3)2
Ca(NO3)2Number of atoms in the compound:Ca- 1N- 2O- 6Find the atomic masses of all atoms and add:Ca = 40.1N = 2 * 14.0 = 28.0O = 6 * 16.0 = 96.0___________________164.1 gEquation:# moles * added atomic mass = # gramsAnswer:4.2 moles * (164.1 g) = 689.22 grams of Ca(NO3)2
156
If you are referring to the nitrate ion, NO3-, the oxidation number of oxygen would be O2- and nitrogen would be N5+. If you are talking about nitrogen trioxide NO3, the oxidation number of oxygen would be O2- and nitrogen would be N6+. Edit: Nitrogen trioxide does not exist in its free state.
Nitrogen trioxide
NO3
N(nitrogen) = 7 electrons 3O(three oxygen) = 3* 8 electrons = 24 electrons 7 electrons + 24 electrons = 31 electrons in NO3 ( nitrogen trioxide ) ==============================