This mass is 244,459.10e23 g.
O3, with a molecular mass of 48 grams per mole
The percentage of oxygen is 54,84 %.
320 grams of oxygen is the equivalent of 10 moles.
16 grams of oxygen how many moles is 0,5 moles.
1
0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.
640 grams of Oxygen
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
62 grams a+
62 grams a+
Wallastonite is a silicate mineral is comprised of calcium, silicon, and oxygen. The molecular formula is CaSi03, with a molecular weight of 116.16 grams per mole.
A sample of a compound contain 1.52 g of Nitrogen and 3.47 g of Oxygen. The molar mass of this compound is between 90 grams and 95 grams. The molecular formula and the accurate molar mass would be N14O35.
O3, with a molecular mass of 48 grams per mole
We assume 100 grams of compound and change % to grams. Get moles. 40 grams S (1 mole S/32.07 grams) = 1.247 60 grams O (1 mole O/16.0 grams) = 3.75 Now, the smallest mole value, sulfur, is 1. Divide the oxygen mole value by the sulfur mole value. 3.75 mole O/1.247 mole S = 3.00 SO3 ------- is the empirical formula
To find empirical formulas, masses of elemental reactants must be changed to gram atoms by dividing the mass by the gram atomic masses of each element. Thus, 16 grams of sulfur constitutes 16/32.06 or 0.50 mole to the justified number of significant digits, and 24 grams of oxygen constitutes 24/15.9994 or 1.50 moles of oxygen to the justified number of significant digits. Therefore, the atomic ratio of oxygen to sulfur in the compound is 1.50/0.50 or 3, and the empirical formula is SO3.
The variables for the formula are incomplete. You would need to know how many grams of butane are put out by the lighter. The molecular weight of butane is 58.12 g/mol, which is also needed to complete the formula.
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?